相同号码的核对表

Question

这是我的代码：

def generate_cards(self):


    self.player1_cards = [
        [random.randint(1, 91), '', random.randint(1, 91), '', random.randint(1, 91), '',
            random.randint(1, 91), '', random.randint(1, 91), random.randint(1, 91), ''],
        [random.randint(1, 91), random.randint(1, 91), '', random.randint(1, 91), '',
            random.randint(1, 91), '', random.randint(1, 91), random.randint(1, 91)],
        [random.randint(1, 91), '', random.randint(1, 91), '', random.randint(1, 91),
         '', random.randint(1, 91), '', random.randint(1, 91)]
    ]

    self.player2_cards = [
        [random.randint(1, 91), '', random.randint(1, 91), '', random.randint(1, 91), '',
            random.randint(1, 91), '', random.randint(1, 91), random.randint(1, 91), ''],
        [random.randint(1, 91), random.randint(1, 91), '', random.randint(1, 91), '',
            random.randint(1, 91), '', random.randint(1, 91), random.randint(1, 91)],
        [random.randint(1, 91), '', random.randint(1, 91), '', random.randint(1, 91),
            '', random.randint(1, 91), '', random.randint(1, 91)]
    ]

    for i in range(0, 3):
        ordered = iter(sorted(x for x in self.player1_cards[i] if x != ''))
        self.player1_cards[i] = [
            next(ordered) if x != '' else '' for x in self.player1_cards[i]]

    for j in range(0, 3):
        ordered1 = iter(
            sorted(x for x in self.player2_cards[j] if x != ''))
        self.player2_cards[j] = [
            next(ordered1) if x != '' else '' for x in self.player2_cards[j]]

    print("Player1:\n", self.player1_cards,
          "\nPlayer 2:\n", self.player2_cards)

在此代码中，我为每个玩家生成 2 张卡片并对其进行排序。 但是，如果生成的数字只使用了 1 次，我必须检查卡的行。 我的意思是如果 player1_cards 中有 9 个，则这张卡中不再有 9 个。

Answer 1

def generate_cards():
    deck = list(range(1, 91))
    random.shuffle(deck)
    player1_cards = [deck.pop() for _ in range(9)]
    player2_cards = [deck.pop() for _ in range(9)]