![](/img/trans.png)
[英]python - Replace values of keys with values corresponding to different keys in the same dictionary
[英]Comparing keys of a dictionary in Python and extracting corresponding values
我不知道什么是数据框。 这是代码和示例输出:
dict_one = {1: [1, 2, 3, 4]}
dict_two = {1: [7, 8, 9, 10]}
all_keys = set(dict_one).union(set(dict_two))
rows = []
for key in all_keys:
dict_one_values = []
if key in dict_one:
dict_one_values = dict_one[key]
dict_two_values = []
if key in dict_two:
dict_two_values = dict_two[key]
for i in range(min(len(dict_one_values), len(dict_two_values))):
rows.append([key, dict_one_values[i], dict_two_values[i]])
for row in rows:
print(*row)
输出:
1 1 7
1 2 8
1 3 9
1 4 10
我会假设这个输入:
dict_1 = {'a': ['b','c','d','e'],'b': ['a','c','d','e'],'p': ['q','r','s']}
dict_2 = {'a': ['x','y','z','n'],'b': ['u','v','w','x','y','z','n']}
如果不是,您可以使用dict_i = {k: literal_eval(v) for k,v in dict_i.items()}
轻松获得它
您可以使用理解来选择预期的数据,并使用它来构建您的数据框:
data = [(k, v1, v2) for k in dict_1 if k in dict_2
for v1, v2 in zip(dict_1[k], dict_2[k])]
df = pd.DataFrame(data)
它给:
0 1 2
0 a b x
1 a c y
2 a d z
3 a e n
4 b a u
5 b c v
6 b d w
7 b e x
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.