无法使用 Python Selenium 选择下拉列表

Question

我想抓取这个网站： http ://sekolah.data.kemdikbud.go.id/ 我想选择“Jenjang”字段，“SMA”值。 之后，需要点击“Cari Sekolah”按钮

不幸的是，我的代码不起作用。 我设法选择了 SMA，但无法单击“Cari Sekolah”开始查询。 任何人都知道如何解决这个问题。 这是我的代码：

from selenium import webdriver
from selenium.webdriver import Chrome
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC
import pandas as pd
import time
from selenium.webdriver.support.ui import Select

option = webdriver.ChromeOptions()
option.add_argument('--incognito')
webdriver = "/Users/rs26/Desktop/learnpython/web/chromedriver"
driver = Chrome(executable_path=webdriver, chrome_options=option)

url="http://sekolah.data.kemdikbud.go.id/"
driver.get(url)
wait = WebDriverWait(driver,15)
select_element = Select(driver.find_element_by_id("bentuk"))
select_element.select_by_value("SMA")
wait.until(EC.element_to_be_clickable((By.XPATH,"//button[text()='Cari Sekolah']"))).click()

Answer 1

请找到以下解决方案以从自定义下拉列表中进行选择

 from selenium import webdriver
    from selenium.webdriver.support.ui import Select
    from selenium.webdriver.support import expected_conditions as EC
    from selenium.webdriver.common.by import By
    from selenium.webdriver.support.ui import WebDriverWait

    # # Solution 1:
    driver = webdriver.Chrome(executable_path=r"C:\New folder\chromedriver.exe")
    driver.get('http://sekolah.data.kemdikbud.go.id/')
    driver.maximize_window()
    element =  WebDriverWait(driver, 10).until(EC.element_to_be_clickable((By.ID, "select2-bentuk-container")))
    element.click()
    list=WebDriverWait(driver, 10).until(EC.element_to_be_clickable((By.XPATH, "//input[@class='select2-search__field']")))
    list.send_keys("SMA")
    select=WebDriverWait(driver, 10).until(EC.presence_of_element_located((By.CLASS_NAME, "select2-results__option")))
    select.click()

Answer 2

您可以使用form button[type=submit] css 选择器来单击。

wait.until(EC.element_to_be_clickable((By.CSS_SELECTOR,"form button[type=submit]"))).click()