[英]input month and year and get output that whole month date
我已经尝试过这段代码,但我想通过使用 where 条件传递月份和年份参数。
WITH d AS
(SELECT TRUNC ( to_date('01.2012','mm.yyyy'), 'MM' ) - 1 AS dt
FROM dual
)
SELECT dt + LEVEL AS date_month
FROM d
CONNECT BY LEVEL <= ADD_MONTHS (dt, 1) - dt
你非常接近解决方案,可以这样做
SQL> var mon number;
SQL> var year number;
SQL> begin :mon :=&mon; :year := &year; end; -- mon --> 4 and year --> 2020
2 /
PL/SQL procedure successfully completed
mon
---------
4
year
---------
2020
SQL>
SQL> WITH d AS
2 (
3 SELECT TRUNC( to_date(lpad(:mon,2,'0')||'.'||:year,'mm.yyyy'), 'MM' ) - 1 AS dt
4 FROM dual
5 )
6 SELECT dt + LEVEL AS date_month
7 FROM d
8 CONNECT BY LEVEL <= ADD_MONTHS (dt, 1) - dt
9 /
列出2020 年 4 月的所有日期。 并将这些参数值替换为所需的月份和年份组合。
您不需要WHERE
子句,您可以将年份和月份作为绑定变量传递:
SELECT month_start + LEVEL - 1 AS date_month
FROM (
SELECT ADD_MONTHS( TRUNC( TO_DATE( :year, 'YYYY' ), 'YYYY' ), :month - 1 )
AS month_start
FROM DUAL
)
CONNECT BY month_start + LEVEL - 1 < ADD_MONTHS( month_start, 1 )
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