如何将 class 类型转换为字符串 selenium python

Question

from selenium import webdriver
web = webdriver.Chrome(r"C:\Users\gohar\PycharmProjects\Parctice\webs\chromedriver.exe")
web.get('https://www.imdb.com/chart/top/?ref_=nv_mv_250')
rating = web.find_elements_by_xpath('//td[@class="ratingColumn imdbRating"]')
moviename = web.find_elements_by_xpath('//td[@class="titleColumn"]')
numrating = len(rating)
for i in range(numrating):
    print(rating[i].text + ' : ' + moviename[i].text)
    web.close()

如何管理我得到的打印件？ 例如，我可以取出评分为 8 的电影

Answer 1

您可以找到以下解决方案来打印电影的特定评级列表：

from selenium import webdriver
web = webdriver.Chrome(executable_path=r"C:\New folder\chromedriver.exe")
web.get('https://www.imdb.com/chart/top/?ref_=nv_mv_250')
rating = web.find_elements_by_xpath('//td[@class="ratingColumn imdbRating"]')
moviename = web.find_elements_by_xpath('//td[@class="titleColumn"]')
numrating = len(rating)
for i in range(numrating):
    if rating[i].text == "9.0":
      print(rating[i].text + ' : ' + moviename[i].text)
web.close()

Output：

使用浮动更新的解决方案

web.get('https://www.imdb.com/chart/top/?ref_=nv_mv_250')
rating = web.find_elements_by_xpath('//td[@class="ratingColumn imdbRating"]')
moviename = web.find_elements_by_xpath('//td[@class="titleColumn"]')
numrating = len(rating)

for i in range(numrating):
    if (float(rating[i].text) )==float(8.2):
      print(rating[i].text + ' : ' + moviename[i].text)
web.close()