我试图让图像出现 onclick，并且脚本没有执行

Question

当您单击页面上的活动图像时，我正在尝试显示单独的图像。

我尝试将 onclick 移动到<a>标记、 <img>标记、 <div>标记中，我尝试使用此脚本命令的不同版本，但似乎没有任何效果。 活动图像和 cursor:pointer 都可以工作，但 java 失败。 有任何想法吗？？

 function opencontact() { var x = document.getElementById("instagram"); if (x.style.display === "none") { x.style.display = "inline"; } else { x.style.display = "none"; } }

 .insta { display: none; position: fixed; top: 180px; right: 220px; z-index: 2; transition: 0s; padding: 0px; }

 <div id="lips2" class="lipbtn2"> <span style="cursor:pointer" onclick="opencontact()"> <a> <img src="https://www.country935.ca/wp-content/uploads/sites/19/2017/07/a-kiss.jpg" width="15%" height="auto" alt="" class="kiss2"> <img src="https://dzasv7x7a867v.cloudfront.net/product_photos/34277616/20150910_011229_1000w.png" width="15%" height="auto" alt="" class="kiss2active"> </a> </span> </div> <div id="instagram" class="insta"> <a href="http://instagram.com/"><img src="https://upload.wikimedia.org/wikipedia/commons/thumb/e/e7/Instagram_logo_2016.svg/1200px-Instagram_logo_2016.svg.png" alt="" width="124px" /> </a> </div>

Answer 1

您需要翻转测试，否则您将不得不单击两次

我不确定你还想发生什么

 function opencontact() { var x = document.getElementById("instagram"); x.style.display = x.style.display === "inline"? "none": "inline" }

 .insta { display: none; position: fixed; top: 180px; right: 220px; z-index: 2; transition: 0s; padding: 0px; }

 <div id="lips2" class="lipbtn2"> <span style="cursor:pointer" onclick="opencontact()"> <a> <img src="https://www.country935.ca/wp-content/uploads/sites/19/2017/07/a-kiss.jpg" width="15%" height="auto" alt="" class="kiss2"> <img src="https://dzasv7x7a867v.cloudfront.net/product_photos/34277616/20150910_011229_1000w.png" width="15%" height="auto" alt="" class="kiss2active"> </a> </span> </div> <div id="instagram" class="insta"> <a href="http://instagram.com/"><img src="https://upload.wikimedia.org/wikipedia/commons/thumb/e/e7/Instagram_logo_2016.svg/1200px-Instagram_logo_2016.svg.png" alt="" width="124px" /> </a> </div>