我在“.txt”文件中有 3 行，每行包含 3 个数字，我想根据用户输入对他们的数字“+1”

Question

所以基本上我有一个包含 3 行的文件，每行有 3 个数字

7,2,1
10,0,0
2,8,0 

然后根据用户输入，我想对该行中的一个数字 +1。

if user_input == 1
     +1 to line1Number1
elif user_input == 2 
     +1 to line1Number2
elif user_input == 3
     +1 to line1Number3
else 
    print"error"

Answer 1

你可以这样做：

In [1634]: user_input = int(input()) 

In [1627]: with open('t.txt', 'r') as f: 
      ...:     lines = f.readlines() 

      ...: for c,l in enumerate(lines): 
      ...:     if c == user_input: 
      ...:         lst = l.split(',') 
      ...:         lst = [int(x) + 1 for x in lst] 
      ...:         print(lst)

[3, 9, 1]

Answer 2

with open(filename, "r") as txtr:
    data = txtr.readlines()
data = [x.split(",") for x in data]
for i in range(len(data)):
    for j in range(len(data[i])):
        data[i][j] = int(data[i][j])

data 现在有 3 个列表，每个列表有 3 个数字。

if user_input == 1
    data[0] = [x+1 for x in data[0]]

只需对 rest 执行相同操作即可。

保存到文本文件：

ndata = [",".join(x) for x in data]
nndata = "\n".join(ndata)
with open(filename, "w") as txtw:
    txtw.write(nndata)

Answer 3

另一种方法（评论中的解释）。 从 in.txt 读取，写入 out.txt。

# ask user input for which column to update
update_column = int(input("Column to update 1,2 or 3?"))
# open file to read from
with open("in.txt", "r") as f:
    # for every line in the text file
    for line in f.readlines():
        # make the numbers into an integer list (remove new line, split by comma, and convert to int)
        new_line = list(map(int, line.strip().split(",")))
        # add one to the number in the column input 
        new_line[update_column -1] +=1
        # open a file for a pending
        with open("out.txt", "a") as of:
            # append the list removing brackets and adding a new line
            of.write(str(new_line).replace("[","").replace("]","") + "\n")