[英]Arduino for loop with delay between each cycle without stopping program
[英]Arduino - stopping loop via button
所以我一直在试验 TinkerCad,等待我的 arduino 到货。 目前我有一个 LED 灯循环,我想通过按下按钮来启动和停止循环。
目前我可以通过按钮启动我的循环,但不能通过按下相同的按钮来停止循环。 这和去抖有关系吗?
const int button = 10;
const int led1 = 8;
const int led2 = 4;
const int led3 = 3;
const int timedelay = 250;
boolean buttonstate = false;
void setup()
{
pinMode(led1, OUTPUT);
pinMode(led2, OUTPUT);
pinMode(led3, OUTPUT);
pinMode(button, INPUT);
}
void loop() {
if(digitalRead(button)==HIGH) // check if button is pushed
buttonstate = !buttonstate; //reverse buttonstate value
if(buttonstate==true)
{
digitalWrite(led1, HIGH);
delay(timedelay);
digitalWrite(led1, LOW);
delay(timedelay);
digitalWrite(led2, HIGH);
delay(timedelay);
digitalWrite(led2, LOW);
delay(timedelay);
digitalWrite(led3, HIGH);
delay(timedelay);
digitalWrite(led2, HIGH);
delay(timedelay);
digitalWrite(led1, HIGH);
delay(timedelay);
digitalWrite(led3, LOW);
delay(timedelay);
digitalWrite(led2, LOW);
delay(timedelay);
digitalWrite(led1, LOW);
delay(timedelay);
digitalWrite(led1, HIGH); }
else {
digitalWrite(led1, HIGH);
}
}
我的电路设置:
编辑:
我已经调整了我的代码,用毫秒替换了延迟,并寻找按钮 state 的变化。 仍在寻找一种方法来在循环结束时调整 interval_led1 以制作生病的 LED 灯序列。
const int led1 = 13;
const int led2 = 8;
const int led3 = 5;
const int button = 10;
int ledState_led1 = LOW; // ledState used to set the LED
int ledState_led2 = LOW;
int ledState_led3 = LOW;
// Generally, you should use "unsigned long" for variables that hold time
// The value will quickly become too large for an int to store
unsigned long previousMillis_led1 = 0; // will store last time LED was updated
unsigned long previousMillis_led2 = 0;
unsigned long previousMillis_led3 = 0;
long interval_led1 = 500; // interval at which to blink (milliseconds)
long interval_led2 = 600;
long interval_led3 = 700;
boolean buttonstate = false;
void setup() {
pinMode(led1, OUTPUT);
pinMode(led2, OUTPUT);
pinMode(led3, OUTPUT);
pinMode(button, INPUT);
}
void loop() {
// check to see if it's time to blink the LED; that is, if the difference
// between the current time and last time you blinked the LED is bigger than
// the interval at which you want to blink the LED.
unsigned long currentMillis_led1 = millis();
unsigned long currentMillis_led2 = millis();
unsigned long currentMillis_led3 = millis();
bool current_state = digitalRead(button);
bool prev_buttonstate= false;
if(current_state==HIGH && current_state != prev_buttonstate)
{
buttonstate = !buttonstate; //reverse buttonstate value
}
prev_buttonstate = current_state;
if(buttonstate==true)
if (currentMillis_led1 - previousMillis_led1 >= interval_led1) {
previousMillis_led1 = currentMillis_led1;
if (ledState_led1 == LOW) {
ledState_led1 = HIGH;
} else {
ledState_led1 = LOW;
}
digitalWrite(led1, ledState_led1);
}
if(buttonstate==true)
if (currentMillis_led2 - previousMillis_led2 >= interval_led2) {
previousMillis_led2 = currentMillis_led2;
if (ledState_led2 == LOW) {
ledState_led2 = HIGH;
} else {
ledState_led2 = LOW;
}
digitalWrite(led2, ledState_led2);
}
if(buttonstate==true)
if (currentMillis_led3 - previousMillis_led3 >= interval_led3) {
previousMillis_led3 = currentMillis_led3;
if (ledState_led3 == LOW) {
ledState_led3 = HIGH;
} else {
ledState_led3 = LOW;
}
digitalWrite(led3, ledState_led3);
}
}
在这里,您的两种情况在延迟方面非常不同: if(buttonstate==true)
由于其中包含多个delay
指令,因此执行时间很长, else
非常快,因为其中没有delay
。
当buttonstate==True
并且您按下按钮时(正如 Delta_G 所说, delay()
在大多数情况下会阻止测试发生,您应该使用millis()
例如进行计时,但是假设您很幸运并且您传递您的第一个if
语句),因此buttonstate
将翻转为false
。
由于您的else
指令没有延迟,因此电路板将立即返回到您的初始if
,不幸的是,由于您的速度不足以仅按下此按钮几微秒,这仍然是true
的。 所以buttonstate
将再次翻转,您的代码将落在您的if(buttonstate==true)
中,它很长,允许您在重新评估if(digitalRead(button)==HIGH)
之前及时释放按钮。
解决方案(除了@Delta_G 提出的计时问题和@TomServo 提出的硬件问题)是寻求按钮state 的更改。 因此,您必须与之前的值进行比较。 您可以声明另一个 boolean boolean prev_buttonstate = false;
并且可以执行以下操作:
bool current_state = digitalRead(button);
if(current_state==HIGH && current_state != prev_buttonstate)
{
buttonstate = !buttonstate; //reverse buttonstate value
}
prev_buttonstate = current_state;
希望能帮助到你!
你的电路是正确的。 如果您按住按钮的时间稍长,则状态将继续保持良好,并且 state 会再次错误地重置。
要模拟切换效果,请使用 bool 变量,如下所示: 当信号变低时,您重置变量。
void loop() {
static bool ready = true;
if(digitalRead(button)==HIGH && ready)
{
ready = false;
buttonstate = !buttonstate; //reverse buttonstate value
if(buttonstate){
digitalWrite(led1, HIGH);
delay(timedelay);
digitalWrite(led1, LOW);
delay(timedelay);
/* Etc*/ }
else {
digitalWrite(led1, HIGH);
}
}
else
if(digitalRead(button)==LOW && !ready)
{
ready = true;
}
}
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