如何使用列表的元素作为键并将矩阵中的相应数字作为值来生成字典？

Question

所以我有一个清单

列表 = ['a','b','c','d','e','f','g']

和一个矩阵文件 in.txt

• 12 15 16 13
• b 9 83 24 72
• c 4 52 17 93
• 12 84 33 80
• 29 25 33 47
• 女 82 11 18 9
• 克 12 21 93 77

我应该如何编写代码，使我的字典键是列表的元素，值是矩阵文件中的数字？ 例如

字典 = {'a':[12,15,16,13],'b':[9,83,24,72].....}

Answer 1

你可以做这样的事情

d = {}                                                                                                                                                                                              

with open('t.txt') as f: 
       for i in f: 
          l = i.split() 
          d[l[0]] = l[1::] 


In [7]: d                                                                                                                                                                                                   
Out[7]: 
{'a': ['12', '15', '16', '13'],
 'b': ['9', '83', '24', '72'],
 'c': ['4', '52', '17', '93'],
 'd': ['12', '84', '33', '80'],
 'e': ['29', '25', '33', '47'],
 'f': ['82', '11', '18', '9'],
 'g': ['12', '21', '93', '77']}

使用 int 值更改行更新为d[l[0]] = list(map(int, l[1::]))

with open('t.txt') as f: 
    for i in f: 
        l = i.split() 
        print(l) 
        d[l[0]] = list(map(int, l[1::])) 

output

Out[18]: 
{'a': [12, 15, 16, 13],
 'b': [9, 83, 24, 72],
 'c': [4, 52, 17, 93],
 'd': [12, 84, 33, 80],
 'e': [29, 25, 33, 47],
 'f': [82, 11, 18, 9],
 'g': [12, 21, 93, 77]}

Answer 2

dict = {}
with open('file.txt', 'r') as f:
    for line in f:
        w = line.split() # w is a list of strings in the current line
        dict[l[0]] = [int(w[i]) for i in range(1, len(w))]
print(dict)