如何根据用户输入运行 def function

Question

我想要“你想喂你的宠物吗？” 随时活跃

  input('Would you like to feed your Pet? ')
  if 

  else:

如果用户输入“是”，它将运行提要 function

def feed(pet):
  if pet['hungry'] == True:
    pet['hungry'] = False
    pet['weight'] = pet['weight'] + 1
  else: print ('Carrot isn\'t hungry right now!')

我是编码新手，无法弄清楚这是如何工作的，谢谢您的帮助。

Answer 1

while(True):
    result=input('would you like to feed your pet?')
    if result=='yes':
        feed(pet)
    x=input('would you like to continue? Yes or No') 
    if x.lower()=='no':   
        break

只需执行上述操作即可无限运行输入并调用 function。 如果您想继续检查，请执行 rest。

Answer 2

您应该将输入设置为等于一个变量。

result=input('would you like to feed your pet?')
if result=='yes':
  //call function feed
else:
//else



//if you want this to go on forever surround it with a while loop like this
while(true):
 result=input('would you like to feed your pet?')
 if result=='yes':
   //call function feed 
 else:
//else

Answer 3

您可以将输入 function 放入像 While(1) 这样的无限循环中

然后在里面写你的输入代码！！ 它会一直等你回答是的！ 虽然没用！

Answer 4

你可以用这个

while true:   
answare= input('Would you like to feed your Pet? ')
if answare == "yes":
   feed(answers)

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