为什么我在 Sequelize 中得到“sequelize.literal is not a function”

Question

我尝试将我的项目克隆到新 PC，然后我收到一个错误调用“sequelize.literal 不是函数”。

这是我的产品 controller。 我尝试通过使用文字 function 来获得具有 avg_rating 的产品。

const Product = require("../models").product;

module.exports = {
getProduct: async (req, res) => {
  try {
    let query = {}
    query.where = {
        isPublished: 1
    };
    query.attributes = {
      include: [
        sequelize.literal(
          `(SELECT CAST(AVG(rating) AS DECIMAL(10,1)) FROM product_reviews WHERE productId = \`Product\`.\`id\`)`
        ),
        "avg_rating",
      ]
    }

    const product = await Product.findAll(query)

    res.send({
      status: 200,
      data: product,
    });

  } catch (error) {
    res.status(500).send({
      error: error.message,
    });
  }
},
}

对于结果

状态 500 和错误：“sequelize.literal 不是函数”

我的 package.json 在这里。

{
  "name": "backend",
  "version": "1.0.0",
  "description": "",
  "main": "app.js",
  "scripts": {
    "dev": "nodemon app.js"
  },
  "author": "NuChaiyakorn",
  "license": "ISC",
  "dependencies": {
    "bcryptjs": "^2.4.3",
    "body-parser": "^1.19.0",
    "cookie-session": "^1.4.0",
    "cors": "^2.8.5",
    "dotenv": "^8.2.0",
    "express": "^4.17.1",
    "express-fileupload": "^1.1.7-alpha.3",
    "express-promise-router": "^3.0.3",
    "faker": "^4.1.0",
    "ffmpeg": "0.0.4",
    "joi": "^14.3.1",
    "jsonwebtoken": "^8.5.1",
    "morgan": "^1.10.0",
    "mysql2": "^2.1.0",
    "passport": "^0.4.1",
    "passport-jwt": "^4.0.0",
    "passport-local": "^1.0.0",
    "ramda": "^0.27.0",
    "randomstring": "^1.1.5",
    "sequelize": "^5.21.6",
    "slugify": "^1.4.0"
  }
}

Answer 1

最后我通过将此行添加到 controller 的顶部来解决问题。

const { sequelize } = require('../models/index')

Answer 2

您的attributes应如下所示 -

query.attributes = [
  [sequelize.literal(`(SELECT CAST(AVG(rating) AS DECIMAL(10,1)) FROM product_reviews WHERE productId = \`Product\`.\`id\`)`), 'avg_rating']
];

您还需要指定响应中所需的额外属性以及avg_rating 。

例如 -

query.attributes = [
  'id',
  ['name','userName'],
  [sequelize.literal(`(SELECT CAST(AVG(rating) AS DECIMAL(10,1)) FROM product_reviews WHERE productId = \`Product\`.\`id\`)`), 'avg_rating']
];

我尝试像您使用的那样将attributes与include一起使用，但没有得到预期的响应。