奇怪的 C++ 错误，不合格的 ID，重新声明

Question

我想创建一个项目，我有 3 个文件，一个test.cpp ， something.h和一个something.cpp 。 他们来了：

测试.cpp：

#include <bits/stdc++.h>
#define f cin
#define g cout
#include "something.h"
using namespace std;

int main(void)
{
    int x;
    register(x);
    return 0;
}

某事.h：

#ifndef __SOMETHING__H_
#define __SOMETHING__H_
#include <bits/stdc++.h>

void register(int x);
#endif

某事.cpp：

#include "something.h"

void register(int x)
{
    std::cout << x << '\n';
}

这是我得到的错误：

In file included from test.cpp:4:0:
something.h:5:15: error: expected unqualified-id before ‘int’
 void register(int x);
               ^~~
something.h:5:15: error: expected ‘)’ before ‘int’
test.cpp: In function ‘int main()’:
test.cpp:10:15: error: ISO C++ forbids declaration of ‘x’ with no type [-fpermissive]
     register(x);
               ^
test.cpp:10:15: error: redeclaration of ‘int x’
test.cpp:9:9: note: ‘int x’ previously declared here
     int x;
         ^
In file included from something.cpp:1:0:
something.h:5:15: error: expected unqualified-id before ‘int’
 void register(int x);
               ^~~
something.h:5:15: error: expected ‘)’ before ‘int’
something.cpp:3:15: error: expected unqualified-id before ‘int’
 void register(int x)
               ^~~
something.cpp:3:15: error: expected ‘)’ before ‘int’

为什么它告诉我我重新定义了 x？ 当我只想用它的值调用寄存器时。

Answer 1

register是 C++ 中的保留字。 因此，您必须提供另一个（未保留的）名称。

更多信息： 在 C++ 中注册关键字 - Thinbug