[英]Generate same encrypted string AES/CBC/PKCS7Padding in Objective C, .net and Android
[英]Problem with decrypt String which is Encrypted in iOS AES/CBC/PKCS7Padding 128 bit Algorithm in Android
在这方面指导我。 我在解密由 iOS“AES/CBC/PKCS7Padding”加密的字符串时遇到问题。 它抛出异常。 我想解密 android 中的字符串,该字符串在 ios 中加密。
在 Android 我遵循这个结构:
For Example:
String text = "rzp_test_DezQO1BVMXhkZY";
String key = "5b0904cfada01b8182bcc029b928244d"; // secret key - 128 bit key
String iv_key ="c999cbd1f130db1d";
我想加密和解密上面提到的“文本”字符串。 如果我只从 Android 进行加密和解密。 然后它工作正常。 但是,如果我尝试解密在 ios 中加密的密钥,则会引发错误。
// Create key and cipher
Cipher dcipher, d1cipher;
IvParameterSpec ivSpec = new IvParameterSpec(iv_key.getBytes());
Key aesKey = new SecretKeySpec(key.getBytes(), "AES");
ecipher = Cipher.getInstance("AES/CBC/PKCS7Padding");
dcipher = Cipher.getInstance("AES/CBC/PKCS7Padding");
ecipher.init(ENCRYPT_MODE, aesKey, ivSpec);
dcipher.init(DECRYPT_MODE, aesKey, ivSpec);
加密算法:
public String encrypt(String str) throws Exception {
// Encode the string into bytes using utf-8
byte[] utf8 = str.getBytes("UTF8");
// Encrypt
byte[] enc = ecipher.doFinal(utf8);
// Encode bytes to base64 to get a string
return Base64.encodeToString(enc, Base64.DEFAULT);
}
解密算法:
public String decrypt(String str) throws Exception {
// Decode base64 to get bytes
String decrypted = "";
try {
byte[] dec = Base64.decode(str, Base64.DEFAULT);
byte[] utf8 = dcipher.doFinal(dec);
// Decode using utf-8
decrypted = new String(utf8, "UTF8").trim();
} catch (Exception e) {
e.printStackTrace();
}
return decrypted;
}
它在 Android 中工作正常,用于加密和解密。 用这个检查:
String encrypted = encrypt(text);
System.out.println("Encrypted String: " + encrypted);
String decrypted = decrypt(encrypted);
System.out.println("Decrypted String: " + decrypted);
问题是从 ios 解密以下加密字符串,这会引发错误:
String decrypted1 = decrypt("c7076c78fc5d9d92c1d86c1500dcc0366ddf1b6e32df00ceadc911239935460d");
System.out.println("Decrypted String1: " + decrypted1);
错误是:
W/System.err: javax.crypto.BadPaddingException: error:1e000065:Cipher functions:OPENSSL_internal:BAD_DECRYPT
W/System.err: at com.android.org.conscrypt.NativeCrypto.EVP_CipherFinal_ex(Native Method)
W/System.err: at com.android.org.conscrypt.OpenSSLCipher$EVP_CIPHER.doFinalInternal(OpenSSLCipher.java:570)
W/System.err: at com.android.org.conscrypt.OpenSSLCipher.engineDoFinal(OpenSSLCipher.java:351)
W/System.err: at javax.crypto.Cipher.doFinal(Cipher.java:1741)
W/System.err: at com.example.aesencryption.Activities.MainActivity1.decrypt(MainActivity1.java:178)
任何人都可以请指导我吗?
在 IOS 中:
使用以下功能。
func aesEncrypt() -> String {
let iv: [UInt8] = Array(AES_IV.utf8)
let key: [UInt8] = Array(AES_SECRET.utf8)
do{
let encrypted = try AES (key: key, blockMode: CBC(iv: iv)).encrypt([UInt8](self.data(using: .utf8)!))
return Data(encrypted).base64EncodedString()
}
catch{
print("error on encrypting data ")
return ""
}
}
func aesDecrypt() -> String {
let iv: [UInt8] = Array(AES_IV.utf8)
let key: [UInt8] = Array(AES_SECRET.utf8)
do{
guard let data = Data(base64Encoded: self) else { return "" }
let decrypted = try AES(key: key, blockMode: CBC(iv: iv), padding: .pkcs7).decrypt([UInt8](data))
return String(bytes: decrypted, encoding: .utf8) ?? self
}
catch{
print("error on encrypting data ")
return ""
}
}
我使用以下方法得到了真正的字符串。
public static String decryptKey(String key_id) {
// Decode base64 to get bytes
String decrypted = "";
try {
Cipher dcipher = Cipher.getInstance("AES/CBC/PKCS7Padding");
dcipher.init(DECRYPT_MODE, aesKey, ivSpec);
byte[] utf8 = dcipher.doFinal(hexToBytes(key_id));
// Decode using utf-8
decrypted = new String(utf8, "UTF8").trim();
} catch (Exception e) {
e.printStackTrace();
}
return decrypted;
}
public static byte[] hexToBytes(String str) {
if (str == null) {
return null;
} else if (str.length() < 2) {
return null;
} else {
int len = str.length() / 2;
byte[] buffer = new byte[len];
for (int i = 0; i < len; i++) {
buffer[i] = (byte) Integer.parseInt(str.substring(i * 2, i * 2 + 2), 16);
}
return buffer;
}
}
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