如何在 jsonb 列中获取参数

Question

我有一张这样的桌子

| id         | reciever                                     
| (bigint)   |(jsonb)                                      
------------------------------------------------------
|    1       | {"name":"ABC","email":"abc@gmail.com"}
|    2       | {"name":"DEF","email":"deef@gmail.com"}

如何获取name where id = 1

output 将是这样的

| id         | name                                     
------------------------------------------------------
|    1       | ABC

Answer 1

使用->> 运算符：

select id, receiver ->> 'name' as name
from the_table
where id = 1;

Answer 2

select id, receiver->'name'
from mytable
where id = 1

Check out other JSON operators and functions on the postgres documentation https://www.postgresql.org/docs/12/functions-json.html

Answer 3

您可以运行以下命令：

SELECT id, receiver->>'name' AS name
FROM mytable
WHERE id = 1;

->>运算符通过给定的键名从 JSON 数据中获取文本值。