![](/img/trans.png)
[英]How to query by a field in an array of sub-documents with greater than condition?
[英]MongoDB How to count where total of sub documents is greater than 3 and sum of sub documents value is greater than 15000
样本数据:
{
"_id" : "5e7b0e1c4669fe48ea07b63a",
"isActive" : false,
"balance" : -1503.89,
"age" : 27,
"eyeColor" : "green",
"name" : "Allison Alvarez",
"gender" : "female",
"company" : "RONELON",
"email" : "allisonalvarez@ronelon.com",
"phone" : "+1 (963) 559-2276",
"address" : "583 Sumpter Street, Stewartville, West Virginia, 110",
"registered" : "2016-10-19T11:45:39 -01:00",
"outstandingloans" : [
{
"id" : 0,
"balance" : -710.65
},
{
"id" : 1,
"balance" : -2979.51
},
{
"id" : 2,
"balance" : -2520.79
},
{
"id" : 3,
"balance" : -3488.78
}
]
}
我正在尝试查找拥有超过 3 笔未偿贷款且余额总和小于 -15000 的男性人数。
到目前为止我的工作是:
db.defaulters.aggregate([
{$match: { "gender" : "male"}},
{$project: {_id: "$name", loansGrt3: {$gte: [{$size: '$outstandingloans'}, 3]} }}
]);
和
db.defaulters.find(
{ $where: "this.outstandingloans.length > 3"}
).count();
db.defaulters.aggregate([
{ $unwind: "$outstandingloans" },
{ $project:
{ _id:1,
size_of_outstandingloans: { $size: "$outstandingloans"},
totalBalance: { $sum: "$outstandingloans.amount" }
}
},
{ $match: { $and: [ {"size_of_outstandingloans": {$gt: 3} }, {"totalBalance": {$lt: -15000} }] }}
])
这给了我正在寻找的答案,以防它对任何人有帮助。不确定它是否完全正确,但它给了我正确的结果。
db.defaulters.aggregate( [
{$match: { gender : "male"}},
{ $unwind: "$outstandingloans" },
{ $group: {
_id: '$_id',
sum: { $sum: '$outstandingloans.balance' },
count: { $sum: 1 }
} },
{$match: { sum : {$lt: -15000}, count: {$gte: 3}}},
{$group: {_id: "$gender", Total: { $sum: 1 }}}
] );
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.