如果 txt 文件的行以另一个 txt 文件中的数字开头 python

Question

with open('D:\Scripting Test/Full Data.txt') as f:
 for line in f:
   with open('D:\Scripting Test/Numbers.txt') as ff:
     for linee in ff:
       if line.startswith(linee):
           print(line)

我想打印文件（full-data.txt）中的所有行，如果它们以文件（numbers.txt）中的任何数字开头

完整数据.txt：

4/0/0        
3/0/7        
4/0/7        
4/0/3        
4/0/4        
4/0/1        
3/0/5        
3/0/1        
2/0/5        
2/0/3        
2/0/4        
2/0/6        
3/0/2        
1/0/3        
6/0/6        
6/0/12       
1/0/5        
1/0/4        
3/0/4        

数字.txt：

1 

2 

5 

8

output 应该是：

2/0/5        
2/0/3        
2/0/4        
2/0/6

1/0/3

1/0/5        
1/0/4

Answer 1

您的问题是，当您阅读某些数字时，它们包含空格，例如换行符和空格。 因此，首先尝试将所有数字读入一个数组并去除所有空格：

nums = []
with open('D:\\Scripting Test\\Numbers.txt') as f:
    nums = f.read().split('\n')
    nums = [n.strip() for n in nums if n != ''] # strip whitespace and get rid of empty lines

with open('D:\\Scripting Test\\Full Data.txt') as f:
    for line in f:
        for num in nums:
            if line.startswith(num):
                print(line)