QObject：无法为不同线程中的父级创建子级。 PyQt5

Question

当我尝试更改滚动区域内的文本浏览器的文本时，出现此 PyQt5 线程错误：

QObject: Cannot create children for a parent that is in a different thread.
(Parent is QTextDocument(0x212e3bb1f50), parent's thread is QThread(0x212e171e220), current thread is QThread(0x212e41dc7e0)

我认为这是因为滚动区域，我无法从我试图更改它的线程访问它，如果我输入相同的代码，它就可以工作......

filepath = "..."
with open(filepath, "r") as f:
    contents = f.read()
    #print(contents)
    self.log_1.setText(contents)

（是的，我知道文件路径是“...”，用于文件安全性。）...在创建滚动区域的线程内部完全可以正常工作。

我唯一不知道的是如何解决这个问题。 我认为您可能能够以某种方式将线程继承到滚动区域，idk。

我的代码，但简化了：

from PyQt5 import QtCore, QtGui, QtWidgets
from mcstatus import MinecraftServer
import threading

class Ui_MainWindow(object):
    def setupUi(self, MainWindow):
        MainWindow.setObjectName("MainWindow")
        MainWindow.resize(1379, 523)
        self.centralwidget = QtWidgets.QWidget(MainWindow)
        self.centralwidget.setObjectName("centralwidget")
        self.scrollArea_1 = QtWidgets.QScrollArea(self.S1)
        self.scrollArea_1.setGeometry(QtCore.QRect(0, 20, 981, 341))
        self.scrollArea_1.setWidgetResizable(True)
        self.scrollArea_1.setObjectName("scrollArea_1")
        self.scrollAreaWidgetContents_1 = QtWidgets.QWidget()
        self.scrollAreaWidgetContents_1.setGeometry(QtCore.QRect(0, 0, 979, 339))
        self.scrollAreaWidgetContents_1.setObjectName("scrollAreaWidgetContents_1")
        self.log_1 = QtWidgets.QTextBrowser(self.scrollAreaWidgetContents_1)
        self.log_1.setGeometry(QtCore.QRect(0, 0, 981, 341))
        self.log_1.setMinimumSize(QtCore.QSize(981, 341))
        self.log_1.viewport().setProperty("cursor", 
        QtGui.QCursor(QtCore.Qt.IBeamCursor))
        self.log_1.setObjectName("log_1")
        self.scrollArea_1.setWidget(self.scrollAreaWidgetContents_1)

    def update1(self, MainWindow):

        threading.Timer(0.2, self.update1, {MainWindow: MainWindow}).start()

        ip = "..."
        port = 25565 #Server 1
        server = MinecraftServer(ip, port)

        try:



            filepath = "..."
            with open(filepath, "r") as f:
                contents = f.read()
                #print(contents)
                self.log_1.setText(contents)



        except IOError as e:

            self.StatusL_1.setText(self.translate("MainWindow", "<html><head/><body><p><span style=\" font-size:18pt;\">Status: Off</span></p></body></html>"))
        else:
            self.StatusL_1.setText(self.translate("MainWindow", "<html><head/><body><p><span style=\" font-size:18pt;\">Status: On</span></p></body></html>"))

Answer 1

您不应该直接从另一个线程修改 GUI，从另一个线程间接修改 GUI 的一种方法是使用 Qt 信号：

import threading
from PyQt5 import QtCore, QtGui, QtWidgets
from mcstatus import MinecraftServer


class Ui_MainWindow(object):
    def setupUi(self, MainWindow):
        # ...


class Worker(QtCore.QObject):
    logged = QtCore.pyqtSignal(str)
    statusChanged = QtCore.pyqtSignal(bool)

    def start(self):
        threading.Timer(0.2, self._execute, daemon=True).start()

    def _execute(self):
        threading.Timer(0.2, self._execute, daemon=True).start()
        ip = "..."
        port = 25565  # Server 1
        server = MinecraftServer(ip, port)

        try:
            filepath = "..."
            with open(filepath, "r") as f:
                contents = f.read()
                self.logged.emit(contents)
        except IOError as e:
            self.statusChanged.emit(False)
        else:
            self.statusChanged.emit(True)


class MainWindow(QtWidgets.QMainWindow, Ui_MainWindow):
    def __init__(self, parent=None):
        super().__init__(parent)
        self.setupUi(self)

        self.worker = Worker()
        self.worker.logged.connect(self.log_1.setText)
        self.worker.statusChanged.connect(self.on_status_changed)
        self.worker.start()

    @QtCore.pyqtSlot(bool)
    def on_status_changed(self, status):
        text = '<html><head/><body><p><span style=" font-size:18pt;">Status: {}</span></p></body></html>'.format(
            "On" if status else "Off"
        )
        self.StatusL_1.setText(text)


if __name__ == "__main__":
    import sys

    app = QtWidgets.QApplication(sys.argv)
    w = MainWindow()
    w.show()
    sys.exit(app.exec_())

QObject：无法为不同线程中的父级创建子级。 PyQt5

问题描述

1 个解决方案

解决方案1
1 已采纳 2020-05-16 20:36:44

QObject：无法为不同线程中的父级创建子级。 PyQt5

问题描述

1 个解决方案

解决方案1 1 已采纳 2020-05-16 20:36:44

解决方案1
1 已采纳 2020-05-16 20:36:44