从 Swift 或 Objective-C 中的字符串中删除确切的词组

Question

我想从 Swift 或 Objective-C 中的字符串中删除单词的精确组合，而不删除单词的一部分。

您可以通过将字符串转换为 arrays 来从字符串中删除单个单词：

NSString *str = @"Did the favored horse win the race?";
NSString *toRemove = @"horse";

NSMutableArray *mutArray = [str componentsSeparatedByString:@" "];
NSArray *removeArray = [toRemove componentsSeparatedByString:@" "];
[mutarr removeObjectsInArray:removeArr];

如果您不关心整个单词，也可以使用以下方法从另一个字符串中删除两个单词字符串：

str = [str stringByReplacingOccurrencesOfString:@"favored horse " withString:@""];

尽管您必须解决间距问题。

但是，这将在以下字符串上失败：

str = [str stringByReplacingOccurrencesOfString:@"red horse " withString:@""];

这将给出“最喜欢的马是否赢得了比赛”

如何在不删除部分单词留下碎片的情况下干净地删除多个单词？

感谢您的任何建议。

Answer 1

// Convert string to array of words
let words = string.components(separatedBy: " ")

// Do the same for your search words
let wordsToRemove = "red horse".components(separatedBy: " ")

// remove only the full matching words, and reform the string
let result = words.filter { !wordsToRemove.contains($0) }.joined(separator: " ")

// result = "Did the favored win the race?"

---

这种方法的警告是它会删除原始字符串中任何位置的那些确切单词。 如果您希望结果仅删除以该确切顺序出现的单词，则只需在参数前面使用空格来replacingOccurrencesOf 。

Answer 2

如果要删除某些单词，请尝试使用此扩展名：

extension String{
func replace(_ dictionary: [String: String]) -> String{
  var result = String()
  var i = -1
  for (of , with): (String, String)in dictionary{
      i += 1
      if i<1{
          result = self.replacingOccurrences(of: of, with: with)
      }else{
          result = result.replacingOccurrences(of: of, with: with)
      }
  }
return result
}
}

如何使用：

let str = "Did the favored horse win the race?"
let dictionary = ["horse ": "", "the ": ""]
let result = str.replace(dictionary)
print("result: \(result)")

Output：

result: Did favored win race?

一句话：

let str = "Did the favored horse win the race?"
let result = str.replacingOccurrences(of: "horse ", with: "", options: .literal, range:nil)
print("result: \(result)")

Output：

result: Did the favored win the race?

不要忘记在要删除的单词中包含空格...希望对您有所帮助

Answer 3

您还可以考虑前导空格并将整个匹配替换为单个空格：

str = [str stringByReplacingOccurrencesOfString:@" red horse " withString:@" "];

或者，您可能需要调整此示例，您可以只使用正则表达式 - 这是他们设计的那种东西，并且 Swift 中的语法很好