Google Apps 脚本 JSON.Parse 在调试时导致“无法连接到服务器”

Question

我绝不是我所谓的“开发人员”，而是涉猎不少。 我正在编写一些应用程序脚本代码来查询 API 并将结果推送到 SQL 中。 我有大部分的工作，但我注意到，当我在 Apps 脚本编辑器中调试时，当我进入以下代码行时，编辑器会在顶部抛出“无法连接到服务器消息。

    var response = UrlFetchApp.fetch(clientApiURL,options);
    var resultSet = JSON.parse(response.getContentText());  <-- this is the line that is crashing the IDE

任何人都知道如何更好地调试这个？ 当我不调试它时，代码似乎正常运行并且 function 正确。 但是有了这个 API，并不是所有的对象都以相同的方式格式化，所以我喜欢使用调试器来检查它们。 当编辑器崩溃时，我可以这样做。

任何帮助/见解将不胜感激。 我还粘贴在 response.getContentText() 的值下方

    {"result":{"lead":[{"id":"332","accountID":null,"ownerID":null,"companyName":"","title":null,"firstName":"RYAN","lastName":"CAVANAUGH","street":null,"city":null,"country":null,"state":null,"zipcode":null,"emailAddress":"email@here.com","website":null,"phoneNumber":null,"officePhoneNumber":null,"phoneNumberExtension":null,"mobilePhoneNumber":null,"faxNumber":null,"description":null,"campaignID":"789934082","trackingID":"202003_5e6fa18a87853a69eb306910","industry":null,"active":"1","isQualified":"1","isContact":"1","isCustomer":"1","status":"4","updateTimestamp":"2020-05-08 20:24:48","createTimestamp":"2020-05-03 20:23:29","leadScoreWeighted":"23","leadScore":"26","isUnsubscribed":"0","leadStatus":"customer","persona":"","product_5e554b933fb5b":""}]},"error":null,"id":"5222020","callCount":"215","queryLimit":"50000"}

这将重现错误：

function test(){
 var obj={"result":{"lead":[{"id":"332","accountID":null,"ownerID":null,"companyName":"","title":null,"firstName":"RYAN","lastName":"CAVANAUGH","street":null,"city":null,"country":null,"state":null,"zipcode":null,"emailAddress":"email@here.com","website":null,"phoneNumber":null,"officePhoneNumber":null,"phoneNumberExtension":null,"mobilePhoneNumber":null,"faxNumber":null,"description":null,"campaignID":"789934082","trackingID":"202003_5e6fa18a87853a69eb306910","industry":null,"active":"1","isQualified":"1","isContact":"1","isCustomer":"1","status":"4","updateTimestamp":"2020-05-08 20:24:48","createTimestamp":"2020-05-03 20:23:29","leadScoreWeighted":"23","leadScore":"26","isUnsubscribed":"0","leadStatus":"customer","persona":"","product_5e554b933fb5b":""}]},"error":null,"id":"5222020","callCount":"215","queryLimit":"50000"} 
 var resultSet = JSON.parse(obj);
}

Answer 1

看问题：

function test(){
 var obj={"result":{"lead":[{"id":"332","accountID":null,"ownerID":null,"companyName":"","title":null,"firstName":"RYAN","lastName":"CAVANAUGH","street":null,"city":null,"country":null,"state":null,"zipcode":null,"emailAddress":"email@here.com","website":null,"phoneNumber":null,"officePhoneNumber":null,"phoneNumberExtension":null,"mobilePhoneNumber":null,"faxNumber":null,"description":null,"campaignID":"789934082","trackingID":"202003_5e6fa18a87853a69eb306910","industry":null,"active":"1","isQualified":"1","isContact":"1","isCustomer":"1","status":"4","updateTimestamp":"2020-05-08 20:24:48","createTimestamp":"2020-05-03 20:23:29","leadScoreWeighted":"23","leadScore":"26","isUnsubscribed":"0","leadStatus":"customer","persona":"","product_5e554b933fb5b":""}]},"error":null,"id":"5222020","callCount":"215","queryLimit":"50000"} 
 var resultSet = JSON.parse(JSON.stringify(obj));
}

但是解析的重点是从不是来自 object 的字符串中返回 object。

但我确实看到了问题。 '无法连接到服务器'

我发现这似乎确实有效知道：

function test(){
 var obj='{"result":{"lead":[{"id":"332","accountID":"","ownerID":"","companyName":"","title":"","firstName":"RYAN","lastName":"CAVANAUGH","street":"","city":"","country":"","state":"","zipcode":"","emailAddress":"email@here.com","website":"","phoneNumber":"","officePhoneNumber":"","phoneNumberExtension":"","mobilePhoneNumber":"","faxNumber":"","description":"","campaignID":"789934082","trackingID":"202003_5e6fa18a87853a69eb306910","industry":"","active":"1","isQualified":"1","isContact":"1","isCustomer":"1","status":"4","updateTimestamp":"2020-05-08 20:24:48","createTimestamp":"2020-05-03 20:23:29","leadScoreWeighted":"23","leadScore":"26","isUnsubscribed":"0","leadStatus":"customer","persona":"","product_5e554b933fb5b":""}]},"error":"","id":"5222020","callCount":"215","queryLimit":"50000"}'; 
 var resultSet = JSON.parse(obj);
 var end="is near";//I just put this here to have a place to stop with debugger running
}

我用“”替换了所有 null 。