Google Apps 腳本 JSON.Parse 在調試時導致“無法連接到服務器”

Question

我絕不是我所謂的“開發人員”，而是涉獵不少。 我正在編寫一些應用程序腳本代碼來查詢 API 並將結果推送到 SQL 中。 我有大部分的工作，但我注意到，當我在 Apps 腳本編輯器中調試時，當我進入以下代碼行時，編輯器會在頂部拋出“無法連接到服務器消息。

    var response = UrlFetchApp.fetch(clientApiURL,options);
    var resultSet = JSON.parse(response.getContentText());  <-- this is the line that is crashing the IDE

任何人都知道如何更好地調試這個？ 當我不調試它時，代碼似乎正常運行並且 function 正確。 但是有了這個 API，並不是所有的對象都以相同的方式格式化，所以我喜歡使用調試器來檢查它們。 當編輯器崩潰時，我可以這樣做。

任何幫助/見解將不勝感激。 我還粘貼在 response.getContentText() 的值下方

    {"result":{"lead":[{"id":"332","accountID":null,"ownerID":null,"companyName":"","title":null,"firstName":"RYAN","lastName":"CAVANAUGH","street":null,"city":null,"country":null,"state":null,"zipcode":null,"emailAddress":"email@here.com","website":null,"phoneNumber":null,"officePhoneNumber":null,"phoneNumberExtension":null,"mobilePhoneNumber":null,"faxNumber":null,"description":null,"campaignID":"789934082","trackingID":"202003_5e6fa18a87853a69eb306910","industry":null,"active":"1","isQualified":"1","isContact":"1","isCustomer":"1","status":"4","updateTimestamp":"2020-05-08 20:24:48","createTimestamp":"2020-05-03 20:23:29","leadScoreWeighted":"23","leadScore":"26","isUnsubscribed":"0","leadStatus":"customer","persona":"","product_5e554b933fb5b":""}]},"error":null,"id":"5222020","callCount":"215","queryLimit":"50000"}

這將重現錯誤：

function test(){
 var obj={"result":{"lead":[{"id":"332","accountID":null,"ownerID":null,"companyName":"","title":null,"firstName":"RYAN","lastName":"CAVANAUGH","street":null,"city":null,"country":null,"state":null,"zipcode":null,"emailAddress":"email@here.com","website":null,"phoneNumber":null,"officePhoneNumber":null,"phoneNumberExtension":null,"mobilePhoneNumber":null,"faxNumber":null,"description":null,"campaignID":"789934082","trackingID":"202003_5e6fa18a87853a69eb306910","industry":null,"active":"1","isQualified":"1","isContact":"1","isCustomer":"1","status":"4","updateTimestamp":"2020-05-08 20:24:48","createTimestamp":"2020-05-03 20:23:29","leadScoreWeighted":"23","leadScore":"26","isUnsubscribed":"0","leadStatus":"customer","persona":"","product_5e554b933fb5b":""}]},"error":null,"id":"5222020","callCount":"215","queryLimit":"50000"} 
 var resultSet = JSON.parse(obj);
}

Answer 1

看問題：

function test(){
 var obj={"result":{"lead":[{"id":"332","accountID":null,"ownerID":null,"companyName":"","title":null,"firstName":"RYAN","lastName":"CAVANAUGH","street":null,"city":null,"country":null,"state":null,"zipcode":null,"emailAddress":"email@here.com","website":null,"phoneNumber":null,"officePhoneNumber":null,"phoneNumberExtension":null,"mobilePhoneNumber":null,"faxNumber":null,"description":null,"campaignID":"789934082","trackingID":"202003_5e6fa18a87853a69eb306910","industry":null,"active":"1","isQualified":"1","isContact":"1","isCustomer":"1","status":"4","updateTimestamp":"2020-05-08 20:24:48","createTimestamp":"2020-05-03 20:23:29","leadScoreWeighted":"23","leadScore":"26","isUnsubscribed":"0","leadStatus":"customer","persona":"","product_5e554b933fb5b":""}]},"error":null,"id":"5222020","callCount":"215","queryLimit":"50000"} 
 var resultSet = JSON.parse(JSON.stringify(obj));
}

但是解析的重點是從不是來自 object 的字符串中返回 object。

但我確實看到了問題。 '無法連接到服務器'

我發現這似乎確實有效知道：

function test(){
 var obj='{"result":{"lead":[{"id":"332","accountID":"","ownerID":"","companyName":"","title":"","firstName":"RYAN","lastName":"CAVANAUGH","street":"","city":"","country":"","state":"","zipcode":"","emailAddress":"email@here.com","website":"","phoneNumber":"","officePhoneNumber":"","phoneNumberExtension":"","mobilePhoneNumber":"","faxNumber":"","description":"","campaignID":"789934082","trackingID":"202003_5e6fa18a87853a69eb306910","industry":"","active":"1","isQualified":"1","isContact":"1","isCustomer":"1","status":"4","updateTimestamp":"2020-05-08 20:24:48","createTimestamp":"2020-05-03 20:23:29","leadScoreWeighted":"23","leadScore":"26","isUnsubscribed":"0","leadStatus":"customer","persona":"","product_5e554b933fb5b":""}]},"error":"","id":"5222020","callCount":"215","queryLimit":"50000"}'; 
 var resultSet = JSON.parse(obj);
 var end="is near";//I just put this here to have a place to stop with debugger running
}

我用“”替換了所有 null 。