如何处理for循环（python）中的错误并继续执行

Question

我试图让我的脚本仍然打印动作 2“print (list1[3])”并跳过动作 1“print (list1[9])”，如果它不能执行它。 如果我的问题不够清楚，我会提前通知我，我会尽力解释这个问题。 我是初学者。

list1 = ['a','b','c','d','f']

try:
  for i in list1:
    #action 1
    print (list1[9])
    #action 2
    print (list1[3])
    break
except:
  pass

Answer 1

只需尝试每个动作，而不是同时尝试两个动作，就像这样

list1 = ['a','b','c','d','f']


for i in list1:
  try:
    #action 1
    print (list1[9])
  except IndexError:
    pass
  try:
    #action 2
    print (list1[3])
  except IndexError:
    pass
  break

Answer 2

尝试这种更清洁的方式

  l = ['a','b','c','d','f']

  # execute the function in try-except
  def try_to_do(fun, index):
     try:
        fun(l[index])
     except:
        pass

  for j in l:
     try_to_do(print, 11)
     try_to_do(print, 1)

  print('Done')

Answer 3

在循环内使用 try except

list1 = ['a','b','c','d','f']

for i in list1:
    try:
        #action 1
        print (list1[9])
    except:
        print(e.with_traceback())
    try:
        #action 2
        print (list1[3])
    except Exception as e:
        print(e.with_traceback())