如何从文本文件中打印字典的排序列表？

Question

所以这个数据文件叫做friends2.txt：

John,555-234-9876,May 5
Mary,556-987-2367,December 12
Albert,555-987-6765,June 12
Leo,555-789-9865,February 25
Ruth,555-786-1238,October 2
Fred,556-235-4536,June 17

但是，我必须创建以名称（即 John）为键的字典，值是电话号码和生日的列表（即。{'John': (555-234-9876, May 5)} .但是,我不确定如何排序(按键值)并一个接一个地打印出文本文件的每一行.目标output是：

Albert 555-987-6765 June 12
Fred 556-235-4536 June 17
John 555-234-9876 May 5
Leo 555-789-9865 February 25
Mary 556-987-2367 December 12
Ruth 555-786-1238 October 2

到目前为止，我的代码：

if __name__ == '__main__':
    file_name = "friends2.txt"
    inf = open(file_name,"r")

    myfriends = {}
    # how to build ? myfriends = {key, list(myfriends[name][0], myfriends[name])}
    for line in inf:
        fields = line.split(",")
        myfriends[fields[0]] = fields[1:]

        # value is a list containing the phone number, in position 0, and the birthday in position 1
        # build a list from the phone number and birthday for the "value" in the key-value pair 

    for name in sorted(myfriends):
        print("{} {} {}".format(sorted(myfriends), myfriends[name][0], myfriends[name][1].strip("\n")))

我试过了

 for name in sorted(myfriends):
        print("{} {} {}".format(sorted(myfriends), myfriends[name][0], myfriends[name][1].strip("\n")))

但这会产生

['Albert', 'Fred', 'John', 'Leo', 'Mary', 'Ruth'] 555-987-6765 June 12
['Albert', 'Fred', 'John', 'Leo', 'Mary', 'Ruth'] 556-235-4536 June 17
['Albert', 'Fred', 'John', 'Leo', 'Mary', 'Ruth'] 555-234-9876 May 5
['Albert', 'Fred', 'John', 'Leo', 'Mary', 'Ruth'] 555-789-9865 February 25
['Albert', 'Fred', 'John', 'Leo', 'Mary', 'Ruth'] 556-987-2367 December 12
['Albert', 'Fred', 'John', 'Leo', 'Mary', 'Ruth'] 555-786-1238 October 2

我将如何使键（名称）正确排序和迭代？ 任何帮助，将不胜感激！

Answer 1

尝试这个：

for name in sorted(myfriends):
    print("{} {} {}".format(name, myfriends[name][0], myfriends[name][1].strip("\n")))

Answer 2

您正在迭代您创建的myfriends字典的键。 您需要使用此键来访问包含您之前存储的字段的字典条目：

for key in sorted(myfriends):
    print("{} {} {}".format(key, myfriends[key][0], myfriends[key][1]))

将条目存储到字典中时，您使用fields[0]作为键，因此您应该将output key到output名称，然后访问myfriends[key][0]和myfriends[key][1]到Z748E6221F6391F63913成为fields[1:] 。

Answer 3

让我知道这是否有帮助：

file_name = "friends.txt"

friends = []
meta_data = ['name', 'phone', 'dob']
with open(file_name,"r") as f:
    for friend in f.readlines():
        friend_attr = friend.strip().split(",")
        friends.append(dict(zip(meta_data, friend_attr)))


sorted_friends = sorted(friends, key=lambda k: k['name']) 
for f in sorted_friends:
    print("{0},{1},{2}".format(f['name'], f['phone'], f['dob']))

Output：

➜  Desktop python stack.py
Albert,555-987-6765,June 12
Fred,556-235-4536,June 17
John,555-234-9876,May 5
Leo,555-789-9865,February 25
Mary,556-987-2367,December 12
Ruth,555-786-1238,October 2