[英]SQL Query to get 2nd most recent results with multiple columns
我正在尝试将 go 的所有不同 part_id(基于 order_date)的第二个最新结果放入我正在制作的报告中,以将其与最新结果进行比较。
评论部分来自我尝试但未成功的另一种方法。
任何帮助是极大的赞赏!
(旁注:我是在 SO 上发帖的新手,如果在其他地方得到回答,我提前道歉,但我找不到与此问题有关的任何内容)
我正在使用以下查询:
SELECT
PURCHASE_ORDER.ORDER_DATE
, PURC_ORDER_LINE.PART_ID
, PURCHASE_ORDER.VENDOR_ID
, PURC_ORDER_LINE.LINE_STATUS
, PURC_ORDER_LINE.ORDER_QTY
, PURC_ORDER_LINE.UNIT_PRICE
--, ROW_NUMBER() over (ORDER BY PURCHASE_ORDER.ORDER_DATE DESC)AS ROW
, CAST (PURC_ORDER_LINE.ORDER_QTY * PURC_ORDER_LINE.UNIT_PRICE AS VARCHAR) AS TOTAL_COST
FROM
PURCHASE_ORDER
INNER JOIN
PURC_ORDER_LINE
ON
PURCHASE_ORDER.ID = PURC_ORDER_LINE.PURC_ORDER_ID
WHERE PURCHASE_ORDER.ORDER_DATE < (SELECT MAX(ORDER_DATE) FROM PURCHASE_ORDER) AND PURC_ORDER_LINE.PART_ID = 'XXXX'
ORDER BY ORDER_dATE DESC
--WHERE PURC_ORDER_LINE.PART_ID = 'XXXX' and PURCHASE_ORDER.ORDER_DATE = (SELECT MAX(ORDER_DATE) FROM PURCHASE_ORDER WHERE ORDER_DATE < (SELECT MAX(ORDER_DATE) FROM PURCHASE_ORDER))
编辑 5/28 深夜:
可以说下面是我需要每个 part_id 的第二个结果的数据集(第二个基于 ORDER_DATE DESC)
+-------------+---------+-----------+
| ORDER_DATE | PART_ID | VENDOR_ID |
+-------------+---------+-----------+
| 2020-05-29 | XXXX | CVVB |
| 2020-05-27 | XXXX | CVVB |
| 2020-05-28 | XXXX | CVVA |
| 2020-05-28 | YYYY | GGNB |
| 2020-04-12 | YYYY | GGNB |
| 2020-02-08 | YYYY | GGNB |
| 2020-05-28 | ZZZZ | LLNB |
| 2019-10-28 | ZZZZ | LLNB |
| 2019-05-27 | ZZZZ | OKIJ |
+-------------+---------+-----------+
我希望收到以下 output(超过 3 个不同的零件 ID):
+------------+---------+-----------+
| ORDER_DATE | PART_ID | VENDOR_ID |
+------------+---------+-----------+
| 2020-05-28 | XXXX | CVVA |
| 2020-04-12 | YYYY | GGNB |
| 2019-10-28 | ZZZZ | LLNB |
+------------+---------+-----------+
查询中还有其他列,但将它们格式化为表会花费更长的时间。 我已经省略了示例中的一些列。
另一个编辑
我不确定这些信息是否有帮助,但我正在尝试将最近的结果与之前的结果进行比较,以显示定价和供应商的差异。 我们正在将数据编译到报表生成器中; 我的方法是创建 2 个单独的数据集,一个是最新的,另一个是第二个最新的,然后在 Report Builder 中合并来自数据集的数据。 如果有更简单的方法并且我正朝着错误的方向前进,请告诉我!
例子:
+------------+---------+-----------+-------------+----------+------------+
| ORDER_DATE | PART_ID | VENDOR_ID | Porder_Date | Ppart_ID | pVendor_id |
+------------+---------+-----------+-------------+----------+------------+
| 2020-05-29 | XXXX | CVVB | 2020-05-28 | XXXX | CVVA |
| 2020-05-28 | YYYY | GGNB | 2020-04-12 | YYYY | GGNB |
| 2020-05-28 | ZZZZ | LLNB | 2019-10-28 | ZZZZ | LLNB |
+------------+---------+-----------+-------------+----------+------------+
编辑第二天早上
感谢大家的帮助。 在 Harry 发布了他的解决方案之后,我继续进行了一些微小的编辑以添加我需要的列。 我用原来的 select 语句交换了他的联合部分。 这里的一切似乎正是我正在寻找的!
代码:
;
WITH mycte AS
(
SELECT
PURCHASE_ORDER.ORDER_DATE
, PURC_ORDER_LINE.PART_ID
, PURCHASE_ORDER.VENDOR_ID
, PURC_ORDER_LINE.LINE_STATUS
, PURC_ORDER_LINE.ORDER_QTY
, PURC_ORDER_LINE.UNIT_PRICE
, CAST (PURC_ORDER_LINE.ORDER_QTY * PURC_ORDER_LINE.UNIT_PRICE AS VARCHAR) AS TOTAL_COST
FROM
PURCHASE_ORDER
INNER JOIN
PURC_ORDER_LINE
ON
PURCHASE_ORDER.ID = PURC_ORDER_LINE.PURC_ORDER_ID
)
, mycte2 AS
(
SELECT
CONVERT(DATE,order_date) AS order_date
, part_id
, vendor_id
, order_qty
, unit_price
, total_cost
, ROW_NUMBER() over(
PARTITION BY part_id
ORDER BY
CONVERT(DATE,order_date) DESC) AS row_num
FROM
mycte
)
SELECT
mycte2.order_date
, mycte2.part_id
, mycte2.vendor_id
, mycte2.order_qty
, mycte2.unit_price
, mycte2.total_cost
, previous.order_date porder_date
, previous.part_id ppart_id
, previous.vendor_id pvendor_id
, previous.order_qty poqrder_qty
, previous.unit_price punit_price
, previous.total_cost ptotal_cost
FROM
mycte2
LEFT JOIN
mycte2 previous
ON
previous.row_num = mycte2.row_num +1
AND mycte2.part_id = previous.part_id
WHERE
mycte2.row_num = 1
我认为这样的事情可以得到第二个最近的订单:
;WITH cteOrders AS (
SELECT ROW_NUMBER() OVER (ORDER BY Order_Date DESC) AS row_num,
PURCHASE_ORDER.ORDER_DATE
, PURC_ORDER_LINE.PART_ID
, PURCHASE_ORDER.VENDOR_ID
, PURC_ORDER_LINE.LINE_STATUS
, PURC_ORDER_LINE.ORDER_QTY
, PURC_ORDER_LINE.UNIT_PRICE
FROM PURCHASE_ORDER
INNER JOIN PURC_ORDER_LINE ON PURCHASE_ORDER.ID = PURC_ORDER_LINE.PURC_ORDER_ID
WHERE PURCHASE_ORDER.ORDER_DATE < (SELECT MAX(ORDER_DATE) FROM PURCHASE_ORDER) AND PURC_ORDER_LINE.PART_ID = 'XXXX'
)
SELECT * FROM cteOrders WHERE row_num = 2
根据您提供的数据,您可以使用 cte 和行号 function 执行此操作。
注意 - 它总是有助于显示整个画面,而不是仅仅要求您需要帮助的部分(通常).. 因为如果我们能够理解整个问题,更容易回答!
请参阅下面的代码
;with mycte as (
select
'2020-05-29' as order_date , 'XXXX' as part_id , 'CVVB' as vendor_id
union all select
'2020-05-27' , 'XXXX' , 'CVVB'
union all select
'2020-05-28' , 'XXXX' , 'CVVA'
union all select
'2020-05-28' , 'YYYY' , 'GGNB'
union all select
'2020-04-12' , 'YYYY' , 'GGNB'
union all select
'2020-02-08' , 'YYYY' , 'GGNB'
union all select
'2020-05-28' , 'ZZZZ' , 'LLNB'
union all select
'2019-10-28' , 'ZZZZ' , 'LLNB'
union all select
'2019-05-27' , 'ZZZZ' , 'OKIJ'
)
, mycte2 as (
Select
convert(date,order_date) as order_date
,part_id
,vendor_id
,ROW_NUMBER() over( partition by part_id order by convert(date,order_date) desc) as row_num
from mycte
)
Select
mycte2.order_date
,mycte2.part_id
,mycte2.vendor_id
,previous.order_date porder_date
,previous.part_id ppart_id
,previous.vendor_id pvendor_id
from mycte2
left join mycte2 previous
on previous.row_num = mycte2.row_num +1
and mycte2.part_id = previous.part_id
where mycte2.row_num = 1
结果
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