[英]SQL Query to get 2nd most recent results with multiple columns
我正在嘗試將 go 的所有不同 part_id(基於 order_date)的第二個最新結果放入我正在制作的報告中,以將其與最新結果進行比較。
評論部分來自我嘗試但未成功的另一種方法。
任何幫助是極大的贊賞!
(旁注:我是在 SO 上發帖的新手,如果在其他地方得到回答,我提前道歉,但我找不到與此問題有關的任何內容)
我正在使用以下查詢:
SELECT
PURCHASE_ORDER.ORDER_DATE
, PURC_ORDER_LINE.PART_ID
, PURCHASE_ORDER.VENDOR_ID
, PURC_ORDER_LINE.LINE_STATUS
, PURC_ORDER_LINE.ORDER_QTY
, PURC_ORDER_LINE.UNIT_PRICE
--, ROW_NUMBER() over (ORDER BY PURCHASE_ORDER.ORDER_DATE DESC)AS ROW
, CAST (PURC_ORDER_LINE.ORDER_QTY * PURC_ORDER_LINE.UNIT_PRICE AS VARCHAR) AS TOTAL_COST
FROM
PURCHASE_ORDER
INNER JOIN
PURC_ORDER_LINE
ON
PURCHASE_ORDER.ID = PURC_ORDER_LINE.PURC_ORDER_ID
WHERE PURCHASE_ORDER.ORDER_DATE < (SELECT MAX(ORDER_DATE) FROM PURCHASE_ORDER) AND PURC_ORDER_LINE.PART_ID = 'XXXX'
ORDER BY ORDER_dATE DESC
--WHERE PURC_ORDER_LINE.PART_ID = 'XXXX' and PURCHASE_ORDER.ORDER_DATE = (SELECT MAX(ORDER_DATE) FROM PURCHASE_ORDER WHERE ORDER_DATE < (SELECT MAX(ORDER_DATE) FROM PURCHASE_ORDER))
編輯 5/28 深夜:
可以說下面是我需要每個 part_id 的第二個結果的數據集(第二個基於 ORDER_DATE DESC)
+-------------+---------+-----------+
| ORDER_DATE | PART_ID | VENDOR_ID |
+-------------+---------+-----------+
| 2020-05-29 | XXXX | CVVB |
| 2020-05-27 | XXXX | CVVB |
| 2020-05-28 | XXXX | CVVA |
| 2020-05-28 | YYYY | GGNB |
| 2020-04-12 | YYYY | GGNB |
| 2020-02-08 | YYYY | GGNB |
| 2020-05-28 | ZZZZ | LLNB |
| 2019-10-28 | ZZZZ | LLNB |
| 2019-05-27 | ZZZZ | OKIJ |
+-------------+---------+-----------+
我希望收到以下 output(超過 3 個不同的零件 ID):
+------------+---------+-----------+
| ORDER_DATE | PART_ID | VENDOR_ID |
+------------+---------+-----------+
| 2020-05-28 | XXXX | CVVA |
| 2020-04-12 | YYYY | GGNB |
| 2019-10-28 | ZZZZ | LLNB |
+------------+---------+-----------+
查詢中還有其他列,但將它們格式化為表會花費更長的時間。 我已經省略了示例中的一些列。
另一個編輯
我不確定這些信息是否有幫助,但我正在嘗試將最近的結果與之前的結果進行比較,以顯示定價和供應商的差異。 我們正在將數據編譯到報表生成器中; 我的方法是創建 2 個單獨的數據集,一個是最新的,另一個是第二個最新的,然后在 Report Builder 中合並來自數據集的數據。 如果有更簡單的方法並且我正朝着錯誤的方向前進,請告訴我!
例子:
+------------+---------+-----------+-------------+----------+------------+
| ORDER_DATE | PART_ID | VENDOR_ID | Porder_Date | Ppart_ID | pVendor_id |
+------------+---------+-----------+-------------+----------+------------+
| 2020-05-29 | XXXX | CVVB | 2020-05-28 | XXXX | CVVA |
| 2020-05-28 | YYYY | GGNB | 2020-04-12 | YYYY | GGNB |
| 2020-05-28 | ZZZZ | LLNB | 2019-10-28 | ZZZZ | LLNB |
+------------+---------+-----------+-------------+----------+------------+
編輯第二天早上
感謝大家的幫助。 在 Harry 發布了他的解決方案之后,我繼續進行了一些微小的編輯以添加我需要的列。 我用原來的 select 語句交換了他的聯合部分。 這里的一切似乎正是我正在尋找的!
代碼:
;
WITH mycte AS
(
SELECT
PURCHASE_ORDER.ORDER_DATE
, PURC_ORDER_LINE.PART_ID
, PURCHASE_ORDER.VENDOR_ID
, PURC_ORDER_LINE.LINE_STATUS
, PURC_ORDER_LINE.ORDER_QTY
, PURC_ORDER_LINE.UNIT_PRICE
, CAST (PURC_ORDER_LINE.ORDER_QTY * PURC_ORDER_LINE.UNIT_PRICE AS VARCHAR) AS TOTAL_COST
FROM
PURCHASE_ORDER
INNER JOIN
PURC_ORDER_LINE
ON
PURCHASE_ORDER.ID = PURC_ORDER_LINE.PURC_ORDER_ID
)
, mycte2 AS
(
SELECT
CONVERT(DATE,order_date) AS order_date
, part_id
, vendor_id
, order_qty
, unit_price
, total_cost
, ROW_NUMBER() over(
PARTITION BY part_id
ORDER BY
CONVERT(DATE,order_date) DESC) AS row_num
FROM
mycte
)
SELECT
mycte2.order_date
, mycte2.part_id
, mycte2.vendor_id
, mycte2.order_qty
, mycte2.unit_price
, mycte2.total_cost
, previous.order_date porder_date
, previous.part_id ppart_id
, previous.vendor_id pvendor_id
, previous.order_qty poqrder_qty
, previous.unit_price punit_price
, previous.total_cost ptotal_cost
FROM
mycte2
LEFT JOIN
mycte2 previous
ON
previous.row_num = mycte2.row_num +1
AND mycte2.part_id = previous.part_id
WHERE
mycte2.row_num = 1
我認為這樣的事情可以得到第二個最近的訂單:
;WITH cteOrders AS (
SELECT ROW_NUMBER() OVER (ORDER BY Order_Date DESC) AS row_num,
PURCHASE_ORDER.ORDER_DATE
, PURC_ORDER_LINE.PART_ID
, PURCHASE_ORDER.VENDOR_ID
, PURC_ORDER_LINE.LINE_STATUS
, PURC_ORDER_LINE.ORDER_QTY
, PURC_ORDER_LINE.UNIT_PRICE
FROM PURCHASE_ORDER
INNER JOIN PURC_ORDER_LINE ON PURCHASE_ORDER.ID = PURC_ORDER_LINE.PURC_ORDER_ID
WHERE PURCHASE_ORDER.ORDER_DATE < (SELECT MAX(ORDER_DATE) FROM PURCHASE_ORDER) AND PURC_ORDER_LINE.PART_ID = 'XXXX'
)
SELECT * FROM cteOrders WHERE row_num = 2
根據您提供的數據,您可以使用 cte 和行號 function 執行此操作。
注意 - 它總是有助於顯示整個畫面,而不是僅僅要求您需要幫助的部分(通常).. 因為如果我們能夠理解整個問題,更容易回答!
請參閱下面的代碼
;with mycte as (
select
'2020-05-29' as order_date , 'XXXX' as part_id , 'CVVB' as vendor_id
union all select
'2020-05-27' , 'XXXX' , 'CVVB'
union all select
'2020-05-28' , 'XXXX' , 'CVVA'
union all select
'2020-05-28' , 'YYYY' , 'GGNB'
union all select
'2020-04-12' , 'YYYY' , 'GGNB'
union all select
'2020-02-08' , 'YYYY' , 'GGNB'
union all select
'2020-05-28' , 'ZZZZ' , 'LLNB'
union all select
'2019-10-28' , 'ZZZZ' , 'LLNB'
union all select
'2019-05-27' , 'ZZZZ' , 'OKIJ'
)
, mycte2 as (
Select
convert(date,order_date) as order_date
,part_id
,vendor_id
,ROW_NUMBER() over( partition by part_id order by convert(date,order_date) desc) as row_num
from mycte
)
Select
mycte2.order_date
,mycte2.part_id
,mycte2.vendor_id
,previous.order_date porder_date
,previous.part_id ppart_id
,previous.vendor_id pvendor_id
from mycte2
left join mycte2 previous
on previous.row_num = mycte2.row_num +1
and mycte2.part_id = previous.part_id
where mycte2.row_num = 1
結果
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