Python 正则表达式替换字符串和句点之间的所有内容，后跟括号

Question

txt = **(Note:** %Program Files% is the default Program Files folder, usually C:\Program Files in Windows 2000, Server 2003, and XP (32-bit), Vista (32-bit), 7 (32-bit), and 8 (32-bit), or C:\Program Files (x86) in Windows XP (64-bit), Vista (64-bit), 7 (64-bit), and 8 (64-bit) **.)** ***IMPORTANT TEXT*** **(Note:** %Application Data% is the current user's Application Data folder, which is usually C:\Documents and Settings\{user name}\Application Data on Windows 2000, XP, and Server 2003, or C:\Users\{user name}\AppData\Roaming on Windows Vista, 7, and 8.. %Program Files% is the default Program Files folder, usually C:\Program Files in Windows 2000, Server 2003, and XP (32-bit), Vista (32-bit), 7 (32-bit), and 8 (32-bit), or C:\Program Files (x86) in Windows XP (64-bit), Vista (64-bit), 7 (64-bit), and 8 (64-bit)**.)** ***IMPORTANT TEXT*** **(Note:** %Application Data% is the current user's Application Data folder, which is usually C:\Documents and Settings\{user name}\Application Data on Windows 2000, XP, and Server 2003, or C:\Users\{user name}\AppData\Roaming on Windows Vista, 7, and 8 **.)**

我有一个像 txt 这样的文本，我想删除 *(NOTE: * and .)之间的所有内容，只删除（重要文本）。 我已经写了这个正则表达式\(Note:([^)]+\.\))但它只找到最后一个注释。 另外，我尝试了\(Note:([^)]+.\))但也考虑了第一个右括号。 我正在使用re.sub(\(Note:([^)]+.\)), '', txt)知道吗？

Answer 1

老实说，这真的很混乱，你可以优化它，但如果模式是一致的，这应该可以工作

**（笔记：**（。*？）**。）**

稍微修改一下你的，这也有效：

\(Note:(.+?\.\))