屏幕中两个位置相同但不同的表格 Position

Question

我在 form1 中新建了一个 form2，设置form2.Location = form1.Location 。 当程序运行时，它们显示在屏幕上的不同位置，但它们的Location.X完全相同。 并且两个X之间有 9 个像素的差异。 太奇怪了。

当我设置overlay.Location = new Point(this.Location.X, this.Location.Y + (Height - ClientSize.Height));

当我设置overlay.Location = new Point(this.Location.X + 9, this.Location.Y + (Height - ClientSize.Height) - 9);

这是代码。

表格1

public partial class Form1 : Form
{
    bool isOverlayGenerated = false;
    TestForm overlay = new TestForm();
    public Form1()
    {
        InitializeComponent();
        VisibleChanged += Form1_VisibleChanged;
        overlay.Size = ClientSize;
        overlay.ShowOnMeMo += () =>
        {
            overlay.memoEdit1.EditValue = $"form1: ({Location.X}, {Location.Y})";
            overlay.memoEdit1.EditValue += Environment.NewLine + $"form2: ({overlay.Location.X}, {overlay.Location.Y})";
        };
        overlay.Owner = this;
    }

    private void Form1_VisibleChanged(object sender, EventArgs e)
    {
        if (!isOverlayGenerated)
        {
            overlay.Location = new Point(this.Location.X, this.Location.Y + (Height - ClientSize.Height));
            //overlay.Location = new Point(this.Location.X + 9, this.Location.Y + (Height - ClientSize.Height) - 9);
            isOverlayGenerated = true;
            overlay.Show();
        }
    }
}

表格2

public partial class TestForm : DevExpress.XtraEditors.XtraForm
{
    public delegate void DoAThing();
    public event DoAThing ShowOnMeMo;
    public TestForm()
    {
        InitializeComponent();
    }

    private void simpleButton1_MouseClick(object sender, MouseEventArgs e)
    {
        ShowOnMeMo?.Invoke();
    }
}

Answer 1

感谢@Dai 的回答，我找到了解决这个问题的方法。

int nonclientWidth = Bounds.Width - ClientSize.Width, nonclientHeight = (Bounds.Height - SystemInformation.CaptionHeight) - ClientSize.Height;
overlay.Location = new Point(this.Location.X + nonclientWidth / 2, this.Location.Y + SystemInformation.CaptionHeight + nonclientHeight / 2);