从包含 json 数组的 json 中提取 jsonb 值

Question

我有 json 列，就像这样的数据 -

{"image_pose_array": [{"image_name": "0026568143_WS.jpg", "image_pose": "EXTRA", "is_blurred": false, "is_dark": false}], "policy_number": "\"D000000000\""}

我如何生成如下所示的报告 -

image_name        | image_pose    |
-----------------------------------
0026568143_WS.jpg |  EXTRA        |

我试过

SELECT  response #>>'{image_pose_array,0}' as json
FROM abcd_abcd.table_data
where policy_number ='D017447997' 
order by request_id  asc;

如何从中提取键的值？

Answer 1

您可以使用#>从数组中访问整个 object，然后访问每个键：

SELECT response #> '{image_pose_array,0}' ->> 'image_name' as image_name, 
       response #> '{image_pose_array,0}' ->> 'image_pose' as image_pose
from abcd_abcd.table_data
where policy_number ='D017447997' 
order by request_id  asc;

#>和#>> （您使用的）之间的区别在于， #>再次返回一个jsonb值，然后可以进一步访问该值。 而#>>返回一个text值。

或者，您可以在“路径”参数中再使用#>>一步：

response #>> '{image_pose_array,0,image_name}' as image_name,
response #>> '{image_pose_array,0,image_pose}' as image_pose

Answer 2

我会使用json[b]_array_elements() 。 这适用于数组包含多个 object 的情况（在这种情况下，查询将为每个嵌入对象生成一行）：

select 
    t.request_id,
    x.obj ->> 'image_name' as image_name,
    x.obj ->> 'image_pose' as image_pose
from digit_bots.t_fourwheeler_analysis_data t
cross join lateral jsonb_array_elements(t.response -> 'image_pose_array') as x(obj) 
where policy_number ='D017447997' 
order by request_id desc