從包含 json 數組的 json 中提取 jsonb 值

Question

我有 json 列，就像這樣的數據 -

{"image_pose_array": [{"image_name": "0026568143_WS.jpg", "image_pose": "EXTRA", "is_blurred": false, "is_dark": false}], "policy_number": "\"D000000000\""}

我如何生成如下所示的報告 -

image_name        | image_pose    |
-----------------------------------
0026568143_WS.jpg |  EXTRA        |

我試過

SELECT  response #>>'{image_pose_array,0}' as json
FROM abcd_abcd.table_data
where policy_number ='D017447997' 
order by request_id  asc;

如何從中提取鍵的值？

Answer 1

您可以使用#>從數組中訪問整個 object，然后訪問每個鍵：

SELECT response #> '{image_pose_array,0}' ->> 'image_name' as image_name, 
       response #> '{image_pose_array,0}' ->> 'image_pose' as image_pose
from abcd_abcd.table_data
where policy_number ='D017447997' 
order by request_id  asc;

#>和#>> （您使用的）之間的區別在於， #>再次返回一個jsonb值，然后可以進一步訪問該值。 而#>>返回一個text值。

或者，您可以在“路徑”參數中再使用#>>一步：

response #>> '{image_pose_array,0,image_name}' as image_name,
response #>> '{image_pose_array,0,image_pose}' as image_pose

Answer 2

我會使用json[b]_array_elements() 。 這適用於數組包含多個 object 的情況（在這種情況下，查詢將為每個嵌入對象生成一行）：

select 
    t.request_id,
    x.obj ->> 'image_name' as image_name,
    x.obj ->> 'image_pose' as image_pose
from digit_bots.t_fourwheeler_analysis_data t
cross join lateral jsonb_array_elements(t.response -> 'image_pose_array') as x(obj) 
where policy_number ='D017447997' 
order by request_id desc