如何阻止我的代码打印额外的问题？

Question

如何停止打印额外的输入行？ 我是 python/编码的新手

class1 = "Math"
class2 = "English"
class3 = "PE"
class4 = "Science"
class5 = "Art"


def get_input(className):
  classInput = raw_input("Enter the score you received for " + className + ": ")
  while int(classInput) >= 101 or int(classInput) <= -1:
    print "Needs to be in the range 0 to 100"
    classInput = raw_input("Enter the score you received for " + className + ": ")
  return int(classInput)


def get_letter_grade(grade):
  if grade >= 93:
    return"A"
  elif grade >= 90:
    return"A-"
  elif grade >= 87:
    return"B+"
  elif grade >= 83:
    return"B"
  elif grade >= 80:
    return"B-"
  elif grade >= 77:
    return"C+"
  elif grade >= 73:
    return"C"
  elif grade >= 70:
    return"C-"
  elif grade >= 67:
    return"D+"
  elif grade >= 63:
    return"D"
  elif grade >= 60:
    return"D-"
  else:
    return"F"

print "Your " + class1 + " score is " + str(get_input(class1)) + ", you got a " + 
get_letter_grade(get_input(class1))

打印出来：

Enter the score you received for Math:  85
Enter the score you received for Math:  85
Your Math score is 85, you got a B

Answer 1

在您的打印中，您调用get_input()方法两次：

print "Your " + class1 + " score is " + str(get_input(class1)) + ", you got a " + 
get_letter_grade(get_input(class1))

您需要做的是通过调用一次get_input()方法来存储您的分数，并在 print 方法中使用存储的值：

score = get_input(class1)
print("Your " + class1 + " score is " + str(score) + ", you got a " +
      get_letter_grade(score))

Answer 2

我会将您对get_input的调用与您的 print 语句分开，不仅在这里，而且通常是这样。

score = str(get_input(class1))
print "Your " + class1 + " score is " + score + ", you got a " + 
get_letter_grade(score)

根据经验，任何用户输入几乎总是应该立即存储在一个变量中，以便以后操作和/或使用。