如何根据在特定页面上按下的下一步按钮调用不同的功能

Question

我正在尝试使用 PyQt5 实现 Qwizard 应用程序，但我无法弄清楚如何根据单击的下一个按钮来调用不同的函数。 显然，下一个按钮属于 Qwizard class，我无法在每个页面上为它们定义特定的行为（如调用不同的函数）。 这是一个例子：

import sys
from PyQt5.QtGui import *
from PyQt5.QtCore import *
from PyQt5.QtWidgets import *

class Window(QWizard):
    def __init__(self):
        super(Window, self).__init__()
        self.firstPage = Page1()
        self.secondPage = Page2()
        self.thirdPage = Page3()
        self.addPage(self.firstPage)
        self.addPage(self.secondPage)
        self.addPage(self.thirdPage)


class Page1(QWizardPage):
    def __init__(self, parent=None):
        super(Page1, self).__init__(parent)
        self.setTitle('''Page 1 Title''')
        self.vLayout = QVBoxLayout()
        self.lineEdit = QLineEdit()
        self.vLayout.addWidget(self.lineEdit)
        self.setLayout(self.vLayout)
        self.registerField('p1_lineEdit*', self.lineEdit, self.lineEdit.text(), self.lineEdit.textChanged)

    def f1(self):
        print("f1")
        if(len(self.lineEdit.text()) < 10):
            self.lineEdit.setText("0" * (10 - len(self.lineEdit.text())) + self.lineEdit.text())
    def validatePage(self):
        self.f1()
        return super(Page1, self).validatePage()

class Page2(QWizardPage):
    def __init__(self):
        super(Page2, self).__init__()
        self.setTitle('''Page 2 Title''')
        self.vLayout = QVBoxLayout()
        self.textBrowser = QTextBrowser()
        self.vLayout.addWidget(self.textBrowser)

        text = f'''Please make sure the provided number: {self.field('p1_lineEdit')} that you previously indicated, is valid.'''
        self.textBrowser.setText(text)
        self.setLayout(self.vLayout)

    def f2(self):
        print("f2")
        print(self.field('p1_lineEdit'))
    def validatePage(self):
        self.f2()
        return super(Page2, self).validatePage()

class Page3(QWizardPage):
    def __init__(self):
        super(Page3, self).__init__()
        self.setTitle('''Page 3 Title''')
    def f3(self):
        print("f3")
    def validatePage(self):
        self.f3()
        return super(Page3, self).validatePage()

def main():
    app = QApplication(sys.argv)
    app.setStyle('plastique')

    window = Window()
    window.setWizardStyle(1)
    window.show()
    app.exec_()

if __name__ == "__main__":
    sys.exit(main())

如何根据 QwizardPage 而不是 Qwizard 区分下一个按钮的行为？ 假设我希望在第 1 页上按下一个按钮后调用 f1()，在第 2 页上按下一个按钮后调用 f2，在第 3 页后按 f3()。

更新：我正在按照有关最小可重现示例和 XY 问题的指南添加已编辑的问题。 单击下一个按钮后，我正在尝试验证特定向导页面上的用户输入，并将其用于填充后续页面。 在这里，我要求在第 1 页输入，假装它很短，并将其插入第 2 页文本浏览器中的文本中间。但是，我看到 None 代替页面文本浏览器内的注册字段 p1_lineEdit 2，但是当我在移动到第 3 页之前在 f2() 中打印它时，我看到了正确的值。 我希望用户在第 2 页加载时观察到正确的值。

import sys
from PyQt5.QtGui import *
from PyQt5.QtCore import *
from PyQt5.QtWidgets import *

class Window(QWizard):
    def __init__(self):
        super(Window, self).__init__()
        self.firstPage = Page1()
        self.secondPage = Page2()
        self.thirdPage = Page3()
        self.addPage(self.firstPage)
        self.addPage(self.secondPage)
        self.addPage(self.thirdPage)


class Page1(QWizardPage):
    def __init__(self, parent=None):
        super(Page1, self).__init__(parent)
        self.setTitle('''Page 1 Title''')
        self.vLayout = QVBoxLayout()
        self.lineEdit = QLineEdit()
        self.vLayout.addWidget(self.lineEdit)
        self.setLayout(self.vLayout)
        self.registerField('p1_lineEdit*', self.lineEdit, self.lineEdit.text(), self.lineEdit.textChanged)

    def f1(self):
        print("f1")
        if(len(self.lineEdit.text()) < 10):
            self.lineEdit.setText("0" * (10 - len(self.lineEdit.text())) + self.lineEdit.text())
    def validatePage(self):
        self.f1()
        return super(Page1, self).validatePage()

class Page2(QWizardPage):
    def __init__(self):
        super(Page2, self).__init__()
        self.setTitle('''Page 2 Title''')
        self.vLayout = QVBoxLayout()
        self.textBrowser = QTextBrowser()
        self.vLayout.addWidget(self.textBrowser)

        text = f'''Please make sure the provided number: {self.field('p1_lineEdit')} that you previously indicated, is valid.'''
        self.textBrowser.setText(text)
        self.setLayout(self.vLayout)

    def f2(self):
        print("f2")
        print(self.field('p1_lineEdit'))
    def validatePage(self):
        self.f2()
        return super(Page2, self).validatePage()

class Page3(QWizardPage):
    def __init__(self):
        super(Page3, self).__init__()
        self.setTitle('''Page 3 Title''')
    def f3(self):
        print("f3")
    def validatePage(self):
        self.f3()
        return super(Page3, self).validatePage()

def main():
    app = QApplication(sys.argv)
    app.setStyle('plastique')

    window = Window()
    window.setWizardStyle(1)
    window.show()
    app.exec_()

if __name__ == "__main__":
    sys.exit(main())

Answer 1

如果要在按下“下一步”按钮时执行 function，则必须使用按下按钮后调用的validatePage()方法来验证是否更改页面：

import sys
from PyQt5.QtGui import *
from PyQt5.QtCore import *
from PyQt5.QtWidgets import *


class Window(QWizard):
    def __init__(self):
        super(Window, self).__init__()
        self.firstPage = Page1()
        self.secondPage = Page2()
        self.thirdPage = Page3()
        self.addPage(self.firstPage)
        self.addPage(self.secondPage)
        self.addPage(self.thirdPage)


class Page1(QWizardPage):
    def validatePage(self):
        self.f1()
        return super(Page1, self).validatePage()

    def f1(self):
        print("f1")


class Page2(QWizardPage):
    def validatePage(self):
        self.f2()
        return super(Page2, self).validatePage()

    def f2(self):
        print("f2")


class Page3(QWizardPage):
    def validatePage(self):
        self.f3()
        return super(Page3, self).validatePage()

    def f3(self):
        print("f3")


def main():
    app = QApplication(sys.argv)
    app.setStyle("plastique")

    window = Window()
    window.setWizardStyle(1)
    window.show()
    app.exec_()


if __name__ == "__main__":
    sys.exit(main())