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Array.sort 按字母顺序按 object 键/值

[英]Array.sort alphabetically by object key/value

所以我有这个包含对象的数组:

var terms = [
 {
  'class-1': {name: 'English', completed: '12/02/19', letterGrade: 'A'}, 
  'class-2': {name: 'Math', completed: '12/02/19', letterGrade: 'A'},
  'class-3': {name: 'P.E.', completed: '12/02/19', letterGrade: 'A'},
  'class-4': {name: 'World History', completed: '12/02/19', letterGrade: 'A'}
 },
 {
  'class-1': {name: 'P.E.', completed: '12/02/19', letterGrade: 'A'},
  'class-2': {name: 'World History', completed: '12/02/19', letterGrade: 'A'},
 },
 {
  'class-1': {name: 'P.E.', completed: '12/02/19', letterGrade: 'A'},
  'class-2': {name: 'English', completed: '12/02/19', letterGrade: 'A'},
  'class-3': {name: 'Math', completed: '12/02/19', letterGrade: 'A'},
 },
 {
  'class-1': {name: 'English', completed: '12/02/19', letterGrade: 'A'},
  'class-2': {name: 'Algebra', completed: '12/02/19', letterGrade: 'A'},
  'class-3': {name: 'Psychology', completed: '12/02/19', letterGrade: 'A'},
 }
]

我想根据 class 的名称按字母顺序对每个嵌套对象进行排序。 但我希望对整个数组进行排序。

不知道我应该如何 go 这样做。 阻碍我的是数据中的嵌套数量。

给定以下输入:

let classes = {
  'class-1': {name: 'P.E.', completed: '12/02/19', letterGrade: 'A'},
  'class-2': {name: 'English', completed: '12/02/19', letterGrade: 'A'},
  'class-3': {name: 'Math', completed: '12/02/19', letterGrade: 'A'},
}

您可以将每个键/值对分成条目,根据需要对这些条目进行排序,然后重新分配给 object,如下所示:

let allEntries = Object.entries(classes)
let sortedEntries = allEntries.sort((a,b) => a[1].name.localeCompare(b[1].name))
let obj = Object.fromEntries(sortedEntries)

这将产生以下结果:

{
  'class-2': {name: 'English', completed: '12/02/19', letterGrade: 'A'},
  'class-3': {name: 'Math', completed: '12/02/19', letterGrade: 'A'},
  'class-1': {name: 'P.E.', completed: '12/02/19', letterGrade: 'A'}
}

虽然请注意插入顺序对于 js object 属性不是确定性的

堆栈片段中的演示

 let classes = { 'class-1': {name: 'PE', completed: '12/02/19', letterGrade: 'A'}, 'class-2': {name: 'English', completed: '12/02/19', letterGrade: 'A'}, 'class-3': {name: 'Math', completed: '12/02/19', letterGrade: 'A'}, } let allEntries = Object.entries(classes) let sortedEntries = allEntries.sort((a,b) => a[1].name.localeCompare(b[1].name)) let obj = Object.fromEntries(sortedEntries) console.log(obj)

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