[英]Array.sort alphabetically by object key/value
所以我有這個包含對象的數組:
var terms = [
{
'class-1': {name: 'English', completed: '12/02/19', letterGrade: 'A'},
'class-2': {name: 'Math', completed: '12/02/19', letterGrade: 'A'},
'class-3': {name: 'P.E.', completed: '12/02/19', letterGrade: 'A'},
'class-4': {name: 'World History', completed: '12/02/19', letterGrade: 'A'}
},
{
'class-1': {name: 'P.E.', completed: '12/02/19', letterGrade: 'A'},
'class-2': {name: 'World History', completed: '12/02/19', letterGrade: 'A'},
},
{
'class-1': {name: 'P.E.', completed: '12/02/19', letterGrade: 'A'},
'class-2': {name: 'English', completed: '12/02/19', letterGrade: 'A'},
'class-3': {name: 'Math', completed: '12/02/19', letterGrade: 'A'},
},
{
'class-1': {name: 'English', completed: '12/02/19', letterGrade: 'A'},
'class-2': {name: 'Algebra', completed: '12/02/19', letterGrade: 'A'},
'class-3': {name: 'Psychology', completed: '12/02/19', letterGrade: 'A'},
}
]
我想根據 class 的名稱按字母順序對每個嵌套對象進行排序。 但我希望對整個數組進行排序。
不知道我應該如何 go 這樣做。 阻礙我的是數據中的嵌套數量。
給定以下輸入:
let classes = {
'class-1': {name: 'P.E.', completed: '12/02/19', letterGrade: 'A'},
'class-2': {name: 'English', completed: '12/02/19', letterGrade: 'A'},
'class-3': {name: 'Math', completed: '12/02/19', letterGrade: 'A'},
}
您可以將每個鍵/值對分成條目,根據需要對這些條目進行排序,然后重新分配給 object,如下所示:
let allEntries = Object.entries(classes)
let sortedEntries = allEntries.sort((a,b) => a[1].name.localeCompare(b[1].name))
let obj = Object.fromEntries(sortedEntries)
這將產生以下結果:
{
'class-2': {name: 'English', completed: '12/02/19', letterGrade: 'A'},
'class-3': {name: 'Math', completed: '12/02/19', letterGrade: 'A'},
'class-1': {name: 'P.E.', completed: '12/02/19', letterGrade: 'A'}
}
雖然請注意插入順序對於 js object 屬性不是確定性的
let classes = { 'class-1': {name: 'PE', completed: '12/02/19', letterGrade: 'A'}, 'class-2': {name: 'English', completed: '12/02/19', letterGrade: 'A'}, 'class-3': {name: 'Math', completed: '12/02/19', letterGrade: 'A'}, } let allEntries = Object.entries(classes) let sortedEntries = allEntries.sort((a,b) => a[1].name.localeCompare(b[1].name)) let obj = Object.fromEntries(sortedEntries) console.log(obj)
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