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[英]Using Python & openpyxl to copy 1 specific row from one excel spreadsheet to another
[英]Openpyxl in python making for loop to merge specific row from many excel files into one
我正在尝试制作一个 python 代码,该代码从 excel 表中取出特定行并将其复制到一个表中。 我想对很多文件(大约 1000 个文件)执行此操作。 因此,我希望每个 excel 文档中的特定行放入目标 excel 文件中的新行中。 我如何修改我的代码来做到这一点?
这是我现在所拥有的:
filename =str('c:\\user\\script\\results\\viktor\\ESS_result_DetectorE503B35_Sewage.xlsx')
wb1 = xl.load_workbook(filename)
ws1 = wb1.worksheets[0]
filename1 ="c:\\user\\script\\results\\viktor\\ESS.xlsx"
wb2 = xl.load_workbook(filename1)
ws2 = wb2.active
mr = 2
mc = ws1.max_column
for i in filename:
for j in range (1, mc + 1):
c = ws1.cell(row = 3, column = j)
ws2.cell(row = 3, column = j).value = c.value
wb2.save(str(filename1))
在你的情况下,你不应该循环filename
字符串,而是filenames
名列表。
filenames = [ur filenames here]
source_xl_filename = r'xxxxxx'
source_wb = xl.load_workbook(source_xl_filename)
ws1 = source_wb.worksheets[0]
def batch_save_xl(filename):
wb2 = xl.load_workbook(filename)
ws2 = wb2.active
mr = 2
mc = ws1.max_column
for i in filename:
for j in range (1, mc + 1):
c = ws1.cell(row = 3, column = j)
ws2.cell(row = 3, column = j).value = c.value
wb2.save(str(filename1))
for filename in filenames:
batch_save_xl(filename)
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