[英]SQL Exclude row based on other rows value
LINE_INVOICE PAYMENT_SOURCE SOURCE_PMT_ID
-1 Payment Received 7369442
1 Payment Received 7369442
2 Payment Received 7369442
3 Payment Received 7369442
4 Payment Received 7369442
5 Payment Received 7369442
6 Payment Received 7369442
7 Payment Received 7369442
8 Payment Received 7369442
9 Payment Received 7369442
10 Payment Received 7369442
11 Payment Received 7369442
12 Payment Received 7369442
我想在“行发票列”中有任何其他数字时删除“-1”行。 这是特定于每个 Source_PMT_ID 的。 如果没有'1'行返回-1。 如何在我的 sql 查询中捕获这个?
我怀疑你想要 window 功能:
select *
from (
select
t.*,
max(case when line_invoice <> -1 then 1 else 0 end)
over(partition by source_pmt_id) flag
from mytable t
) t
where line_invoice <> -1 or flag = 0
子查询中的 window max()
检查是否至少存在一行具有相同的source_pmt_id
和line_invoice
值而不是-1
。 外部查询使用该信息过滤掉line_invoice
值为-1
的行,同时保留那些对于同一source_pmt_id
没有其他值的行。
假设 -1 是最小的数字,并且 line_invoice 从那里上升:
select *
from table1 tab
where LINE_INVOICE >= case when (select max(line_invoice)
from table1 tb_
where tb_.payment_source = tab.payment_source
and tb_.source_pmt_id = tab.source_pmt_id) = -1 then -1 else 0 end
window 功能的一种方法:
select t.*
from (select t.*, max(line_invoice) over (partition by SOURCE_PMT_ID) as max_line_invoice
from t
) t
where line_invoice > -1 or max_line_invoice = -1;
或者,没有子查询:
select t.*
from t
order by row_number() over (partition by source_pmt_id
order by case when line_invoice <> -1 then 1 else 2 end
)
fetch first 1 row with ties;
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