我知道为什么我会收到意外的 { 令牌，但当我的 php 需要将数据集合发送到 javascript 时，我不知道如何修复它

Question

我正在使用这个 javascript 获取代码从 php 获取数据

 async sendRequest(selectValue=this.selectValue){

    const fetchResponse = await fetch('/server/getLastWords.php?select='+selectValue);
    const fetchJSON = await fetchResponse.json();
    await console.log(fetchJSON);
}

这是与 MYSQL 通信并将数据发送到 javascript 的 php 代码

<?php 
 header('Content-Type: application/json');
include 'db/db_connection.php';
$mysqli = new mysqli('localhost','root','','worddb');
if(connectDB($mysqli)){
    $mysqliQuery = "SELECT * FROM wordlist ORDER BY wordIndex DESC LIMIT ?";
    $stmt = $mysqli->stmt_init();
    if(!$stmt->prepare($mysqliQuery)){
        print "Failed to prepare statement\n";
    }else{
        $stmt->bind_param("i", $_GET['select']);
        $stmt->execute();
        $result = $stmt->get_result();
        $resultJSON;
        foreach($result as $resultArray){
            $resultJSON = json_encode($resultArray);
            echo $resultJSON;
        }
    }
}
?>

这个 php 返回

{"wordIndex":94,"english":"seemingly","korean":"\uc678\uacac\uc0c1\uc73c\ub85c, 
\uac89\ubcf4\uae30\uc5d0\ub294","swedish":"till synes","synonyms":"apparently","example":"Seemingly, 
he borrowed the money from the bank"}
{"wordIndex":93,"english":"evade","korean":"\ud53c\ud558\ub2e4, 
\ud68c\ud53c\ud558\ub2e4","swedish":"undvika","synonyms":"elude, evoid","example":"He is using the 
same tactics of distract and evade as the Chancellor used during his speech"} 
{"wordIndex":92,"english":"eclipse","korean":"\uac00\ub9ac\ub2e4, \ube5b\uc744 
\uc783\uc74c","swedish":"f\u00f6rm\u00f6rka","synonyms":"blocking, beating","example":"Her work was 
in eclipse for most of the 20th century"}
{"wordIndex":91,"english":"impede","korean":"\uc9c0\uc5f0\uc2dc\ud0a4\ub2e4",
"swedish":"f\u00f6rhindra","synonyms":"delay, hinder","example":"This will impede learning, 
 essentially causing more problems than solutions"} 
 {"wordIndex":90,"english":"exposure","korean":"\uc704\ud5d8\uc5d0 \ub178\ucd9c, 
 \ud3ed\ub85c","swedish":"exponering","synonyms":"subjection, uncovering","example":"God knows you 
  probably saved my life, at least from exposure or pneumonia"}

我知道它显示了意外的令牌 { 因为 php 正在返回多个 json 对象，因为

当我只回显一个 json 对象时，它工作正常。

        $resultJSON;
        foreach($result as $resultArray){
            $resultJSON =json_encode($resultArray);
        }
        echo($resultJSON);

但我的 php 需要发送所有项目，但我不知道该怎么做，因为控制台显示了意外的令牌 {}

我在发布我的问题之前阅读了这篇文章为什么我会收到意外的“}”？ 但是这篇文章中的解决方案是添加分号，但我的代码中有分号..

Answer 1

这里出错了：

$resultJSON;
foreach($result as $resultArray){
    $resultJSON = json_encode($resultArray);
    echo $resultJSON;
    }

你输出：

echo json1;  
echo json2;
echo json3;

但是，在客户端，输出被收集并视为一个 json。 所以 javascript 将与json1json2json3一起json1json2json3 。 这不是有效的 json。

如果您不必做任何其他事情，则将结果发回

echo json_encode($result);

会做。

Answer 2

将结果转换为数组：

$resultJSON = array();
foreach($result as $resultArray){
    $resultJSON[] = $resultArray;
}

然后输出数组：

echo json_encode($resultJSON);