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[英]How to run SUM() OVER PARTITION BY for COUNT DISTINCT
[英]How to use distinct and count with partition by
我想要具有不同 agt_id 的行以及计数。 以下是我目前正在使用的查询,但需要帮助才能获得不同的行。
with cust as
(
SELECT customer_id, cnic
FROM customer
where customer_id
not in
(select agent_id from agent
where to_date(created_on) BETWEEN '2020-06-01' AND '2020-06-30')
)
select agt.agent_id, c.customer_id, c.cnic, agt.transaction_type_id,
agt.transaction_type_name , row_number() OVER(PARTITION BY c.customer_id) AS agent_count
from cust as c
INNER JOIN konnect_ag_transaction_vw agt ON c.cnic= agt.receiver_cnic
where
agt.status ='PROCESSED'
AND agt.transaction_type_id IN (1,2,3)
当前 Output 使用上述查询:
agt_id cus_id Count
1 89563 93587 7
2 89563 93587 7
3 89563 93587 7
4 89563 93587 7
5 89563 93587 7
6 56139 93587 7
7 56139 93587 7
上面output中的计数是具有相同 cus_id 的行的总数,其中我想要具有相同 cus_id 的 agt_id 链接计数
所需的 output:
agt_id cus_id Count
1 89563 93587 2
2 56139 93587 2
如果我理解正确,您需要一个简单的 group by with count()
with cust as
(
SELECT customer_id, cnic
FROM konnect_bb_customer_vw
where customer_id
not in
(select agent_id from konnect_bb_agent_h_vw
where to_date(created_on) BETWEEN '2020-06-01' AND '2020-06-30')
)
select agt.agent_id, c.customer_id, count(*)
from cust as c
INNER JOIN konnect_ag_transaction_vw agt ON c.cnic= agt.receiver_cnic
where agt.status ='PROCESSED' AND agt.transaction_type_id IN (1,2,3)
group by agt.agent_id, c.customer_id
我怀疑你想要聚合:
select agt.agent_id, c.customer_id, count(*)
from cust c join
konnect_ag_transaction_vw agt
on c.cnic = agt.receiver_cnic
where agt.status = 'PROCESSED' and
agt.transaction_type_id in (1, 2, 3)
group by agt.agent_id, c.customer_id;
使用 DISTINCT 关键字
select DISTINCT agt.agent_id, c.customer_id, c.cnic, agt.transaction_type_id,
agt.transaction_type_name , row_number() OVER(PARTITION BY c.customer_id) AS agent_count
from cust as c
INNER JOIN konnect_ag_transaction_vw agt ON c.cnic= agt.receiver_cnic
where
agt.status ='PROCESSED'
AND agt.transaction_type_id IN (1,2,3)
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