[英]improving plotting of probability density functions in ggplot2
我正在使用 ggplot 绘制多个已知的密度函数,例如伽马密度 function:
library(tidyverse)
apar<-c(1,2,7.5,9)
bpar<-c(2,2,1.3,0.5)
gmaxlim<-c(0, 25)
pgma1<-ggplot(data = data.frame(x = gmaxlim), aes(gmaxlim)) +
stat_function(fun = dgamma, n = 101, args = list(shape = apar[1], scale = bpar[1]),aes(color="black")) +
stat_function(fun = dgamma, n = 101, args = list(shape = apar[2], scale = bpar[2]),aes(color="red")) +
stat_function(fun = dgamma, n = 101, args = list(shape = apar[3], scale = bpar[3]),aes(color="blue")) +
stat_function(fun = dgamma, n = 101, args = list(shape = apar[4], scale = bpar[4]),aes(color="green")) +
ylab(expression(paste("f(x|",alpha,",",beta,")"))) +xlab("x") + scale_x_continuous(breaks=seq(gmaxlim[1],gmaxlim[2], by =5)) +
scale_color_identity(name = "",
breaks = c("black", "red", "blue","green"),
labels = c(substitute(paste(alpha,"= ", v," ,",beta,"= ",s),list(v=apar[1],s=bpar[1])),
substitute(paste(alpha,"= ", v," ,",beta,"= ",s),list(v=apar[2],s=bpar[2])),
substitute(paste(alpha,"= ", v," ,",beta,"= ",s),list(v=apar[3],s=bpar[3])),
substitute(paste(alpha,"= ", v," ,",beta,"= ",s),list(v=apar[4],s=bpar[4]))),
guide = "legend")+
theme_bw()
pgma1
由代表 package (v0.3.0) 于 2020 年 7 月 31 日创建
然而,这段代码远非高效,而且违背了 ggplot 的理念(也许是因为我们没有绘制任何“真实”数据集?)。 有没有办法更有效地编写这个并且可以扩展到不同数量的参数对? 我只想有一行stat_function
并在可能的情况下简化scale_color_identity
。 在颜色标签中保留数学表达式是强制性的
也许使用一些 lapply?
library(tidyverse)
apar <- c(1,2,7.5,9)
bpar <- c(2,2,1.3,0.5)
gmaxlim <- c(0, 25)
mycols <- c("black", "red", "blue", "green")
ggplot(data = data.frame(x = gmaxlim), aes(gmaxlim)) +
lapply(seq_along(apar), function(i){
stat_function(fun = dgamma, n = 101,
args = list(shape = apar[i], scale = bpar[i]), aes( color=mycols[i]))
}) +
scale_color_identity(name="", breaks = mycols,
labels = lapply(seq_along(apar), function(i)
substitute(paste(alpha,"= ", v," ,",beta,"= ",s),
list(v=apar[i], s=bpar[i]))), guide = "legend") +
theme_bw()
由代表 package (v0.3.0) 于 2020 年 7 月 31 日创建
我有点困惑为什么这么多人试图用ggplot
中的stat
函数做这么多,而不是将他们真正想要的数据传递给 plot。 使用stat_function
可以很好地直接绘制奇数线,但试图强迫它做复杂的事情,比如通过引用外部向量来绘制分布族,这似乎很难做到。
更容易推理并且需要更少的代码,只需计算出您想要 plot 和 plot 的内容:
apar <- c(1, 2, 7.5, 9)
bpar <- c(2, 2, 1.3, 0.5)
x <- seq(0, 25, 0.25)
y <- as.vector(sapply(1:4, function(i) dgamma(x, apar[i], scale = bpar[i])))
df <- data.frame(x = rep(x, 4), y, group = rep(letters[1:4], each = length(x)))
labs <- sapply(1:4, function(i) {
substitute(paste(alpha,"= ", v," ,",beta,"= ",s),
list(v = apar[i], s = bpar[i]))})
ggplot(data = df, aes(x, y)) + geom_line(aes(color = group)) +
ylab(expression(paste("f(x|", alpha, ",", beta,")"))) +
scale_color_manual(values = c(1, 2, 4, 3), labels = labs) +
theme_bw()
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.