[英]How to get a specifict part of a string inside a list?
我有一个List
:
Old_list =['orders_ce_deduped.01.csv','orders_ce_deduped.02.csv']
我需要获取01
和02
部分并使用python
将其存储到另一个list
中
new_list = ['01','02']
如果您的 csv 文件名与您的示例一致('~~~.number.csv')
这可能会奏效
new_list = [i.split('.')[1] for i in Old_list]
你可以试试这个:
new_list = []
for i in old_list:
cur = i.split('.')[-2]
new_list.append(cur)
print(new_list)
#Output
['01','02']
如果您专门查找两个句点(“.XXX.”)内的数字,则可以使用正则表达式:
import re
Old_list =['orders_ce_deduped.01.csv','orders_ce_deduped.02.csv']
pattern = re.compile(r"\.(\d+)\.")
new_list = [re.findall(pattern, string)[0] for string in Old_list]
print(new_list)
# Output
['01', '02']
方法一:
Old_list =['orders_ce_deduped.01.csv','orders_ce_deduped.02.csv']
new_list = []
for i in range(len(Old_list)):
new_list.append(Old_list[i][18:20])
print(new_list)
方法二:列表理解
Old_list =['orders_ce_deduped.01.csv','orders_ce_deduped.02.csv']
new_list = []
[new_list.append(Old_list[i][18:20]) for i in range(len(Old_list))]
print(new_list)
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