Python：如何从字典中获取最高键，一旦找到就获取键/值？

Question

嘿伙计们，我有一本字典显示：

Shows = {177.17: ['SELECT * FROM `breaking.bad` '], 190.16: ['SELECT * FROM `breaking.bad`'], 81.72: ['SELECT * FROM `mad.men`'], 74.36: ['SELECT * FROM `game.of.thrones`'], 74.37: ['SELECT * FROM `game.of.thrones`']}

在这里，如果出现这些键值，我想匹配一个列表：

list = ['breaking.bad','mad.men','game.of.thrones','the.mandalorian']

目前我想要实现的是，一旦列表值与字典中的列表匹配，我就会得到这些键的最高值及其值。

到目前为止我所做的是：

for key ,value in Shows.items():
    for lst in list:
        if lst in value and 'breaking.bad' in value and max(key) :
            print(lst)

有什么想法可以帮助实现我的目标吗？

Answer 1

不是最有效的方法，但首先遍历“表”，然后获取每个节目的字典并找到最大值

shows = {177.17: ['SELECT * FROM `breaking.bad` '], 190.16: ['SELECT * FROM `breaking.bad`'], 81.72: ['SELECT * FROM `mad.men`'], 74.36: ['SELECT * FROM `game.of.thrones`'], 74.37: ['SELECT * FROM `game.of.thrones`']}
tables = ['breaking.bad','mad.men','game.of.thrones','the.mandalorian']


for table in tables:  # don't name variables as list
    sub_shows = {key:value for key,value in shows.items() if any(table in v for v in value)}
    if sub_shows:  # max throws error if list is empty
        print(max(sub_shows), table)

Output

190.16 breaking.bad
81.72 mad.men
74.37 game.of.thrones

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我质疑只有一个项目的列表的用例，或者为什么你需要在字典中查询 SQL