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[英]How do I remove the curly bracket in my output of dictionary and replace with output i prefer?
[英]How to remove curly bracket from the output in python?
我是 Python 新手,我最近 1 周前开始学习,但我被困在这里......任何帮助将不胜感激......
from tkinter import *
import tkinter as tk
import psycopg2
root = Tk()
def get_info(Employee_Name, Department, Education,Salary):
con = psycopg2.connect(dbname = 'postgres',user = 'postgres',password = 'Gaurav@31',host = 'localhost',port = 5432)
cur = con.cursor()
query = ('''INSERT INTO Employee (Employee_name, Department, Education,Salary) VALUES (%s,%s,%s,%s);''' )
cur.execute(query,(Employee_Name, Department, Education,Salary))
print('Data inserted Successfully')
con.commit()
con.close()
display_all()
def search(emp_id):
con = psycopg2.connect(dbname = 'postgres',user = 'postgres',password = 'Gaurav@31',host = 'localhost',port = 5432)
cur = con.cursor()
query = ('''SELECT * FROM EMPLOYEE WHERE emp_id = %s;''' )
cur.execute(query,(emp_id))
row = cur.fetchone()
display_search(row)
con.commit()
con.close()
def display_search(row):
listbox = Listbox(frame, width =50 , height=1)
listbox.grid(row = 9 , column =1)
listbox.insert(END,row)
def display_all():
con = psycopg2.connect(dbname = 'postgres',user = 'postgres',password = 'Gaurav@31',host = 'localhost',port = 5432)
cur = con.cursor()
query = ('''SELECT * FROM Employee;''' )
cur.execute(query)
row = cur.fetchall()
listbox = Listbox(frame, width =50 , height=8)
listbox.grid(row = 10 , column =1)
for x in row:
listbox.insert(END,x)
canvas = Canvas(root, height = 480, width = 900)
canvas.pack()
frame = Frame()
frame.config(background="Black")
frame.place(relx = 0, rely = 0, relwidth = 1, relheight = 1)
label = Label(frame,text = " Employee Database")
labelfont = ('times', 24, 'bold')
label.config(bg = 'Black',fg ='Yellow',font =labelfont)
label.grid(row=0,column=1,sticky = N)
label = Label(frame, text = 'Employee Name : ')
labelfont1 = ('times', 18, 'bold')
label.config(bg = 'Black',fg ='Yellow',font =labelfont1)
label.grid(row =1, column = 0,sticky='w')
entry_name = Entry(frame,width = 30)
entry_name.grid(row = 1, column= 1)
label = Label(frame, text = 'Department : ')
labelfont1 = ('times', 18, 'bold')
label.config(bg = 'Black',fg ='Yellow',font =labelfont1)
label.grid(row =2, column = 0, sticky ='w')
dept_name = Entry(frame,width = 30)
dept_name.grid(row = 2, column= 1)
label = Label(frame, text = 'Education : ')
labelfont1 = ('times', 18, 'bold')
label.config(bg = 'Black',fg ='Yellow',font =labelfont1)
label.grid(row =3, column = 0,sticky ='w')
education = Entry(frame,width = 30)
education.grid(row = 3, column= 1)
label = Label(frame, text = 'Salary : ')
labelfont1 = ('times', 18, 'bold')
label.config(bg = 'Black',fg ='Yellow',font =labelfont1)
label.grid(row =4, column = 0, sticky ='w')
salary = Entry(frame,width = 30)
salary.grid(row = 4, column= 1)
button = Button(frame, text = 'Add Information', command=lambda: get_info(entry_name.get(),dept_name.get(),education.get(),salary.get()))
buttonfont1 = ('times', 13, 'bold')
button.config(bg = 'Black',fg ='Yellow',font =buttonfont1)
button.grid(row = 5 , column= 1)
label = Label(frame, text = 'Search by Emp_id : ')
labelfont1 = ('times', 14, 'bold')
label.config(bg = 'Black',fg ='Yellow', font =labelfont1)
label.grid(row = 6, column = 0, sticky ='w')
id_search = Entry(frame,width = 30)
id_search.grid(row = 6, column= 1)
button = Button(frame, text = 'Search',command = lambda: search(id_search.get()))
buttonfont1 = ('times', 13, 'bold')
button.config(bg = 'Black',fg ='Yellow',font =buttonfont1)
button.grid(row = 7 , column= 1)
display_all()
root.mainloop()
请找到附加的代码以及屏幕截图:
我将删除列表框中可见的大括号,以及我希望以表格形式打印
您正在将列表或元组而不是字符串插入到列表框中。 在传递给插入方法之前,您需要将每一行显式转换为字符串。 否则,底层 tcl 解释器将尝试通过在将值转换为字符串时添加花括号或反斜杠来保留数据的类似列表的结构。
考虑这个代码:
query = ('''SELECT * FROM Employee;''' )
cur.execute(query)
row = cur.fetchall()
row
列表列表。 对于row
每个项目,您都有该行中每一列的值列表。
稍后,您将每一行添加到列表框中,如下所示:
for x in row:
listbox.insert(END,x)
如前所述, x
是每列的数据列表。 但是, listbox.insert
需要一个字符串。 由于它不是字符串,tkinter 将使用其自己的逻辑将其转换为字符串,这可能会导致添加花括号。
为避免这种情况,您应该在调用insert
之前将列表显式转换为字符串。 最简单的方法是在每个元素之间添加一个空格:
listbox.insert(END, " ".join(x))
如果“x”包含字符串以外的内容,则需要先将它们转换为字符串。 最终版本可能如下所示:
string_data = [str(data) for data in x]
listbox.insert(END, " ".join(string_data))
布莱恩的解释非常有帮助!!! 但是,当我使用建议的代码时,
string_data = [str(data) for data in x]
listbox.insert(END, " ".join(string_data))
我的输出是一条长线。 所以我添加了一个for循环,
item = [str(data) for data in backend.view()]
for x in item:
lb.insert(END, "".join(x)) # don't include space between quotes
它看起来好一点。 我也尝试过更多的代码,这也很好用,
for item in backend.view():
lb.insert(END, "{}".format(item))
它与 Bryan 建议的代码相同,除了我使用格式而不是连接。
不管怎样,非常感谢! 这非常有帮助。
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