Javascript - 如何从给定的周数和年份中获取一周中的每个日期

Question

如何从给定的周数获得一周内的每个工作日（周一到周五）

输入

var weekNumber = "week + " " + year"; //"35 2020"

想要的输出

var weekArray = ["2020-08-24", "2020-08-25", "2020-08-26", "2020-08-27", "2020-08-28"];

Answer 1

这是建立在以下基础上的示例： javascript 从周数计算日期

获取一周的第一个日期，然后返回一个包含 7 个元素的数组，每个元素的日期递增。

如果天数超过该月的天数，则将月份temp.m加一并将天temp.d重置为一。

 function getISOWeek(w, y) { var simple = new Date(y, 0, 1 + (w - 1) * 7); var dow = simple.getDay(); var ISOweekStart = simple; if (dow <= 4) ISOweekStart.setDate(simple.getDate() - simple.getDay() + 1); else ISOweekStart.setDate(simple.getDate() + 8 - simple.getDay()); const temp = { d: ISOweekStart.getDate(), m: ISOweekStart.getMonth(), y: ISOweekStart.getFullYear(), } //console.log(ISOweekStart) const numDaysInMonth = new Date(temp.y, temp.m + 1, 0).getDate() return Array.from({length: 7}, _ => { if (temp.d > numDaysInMonth){ temp.m +=1; temp.d = 1; // not needed, Date(2020, 12, 1) == Date(2021, 0, 1) /*if (temp.m >= 12){ temp.m = 0 temp.y +=1 }*/ } return new Date(temp.y, temp.m, temp.d++).toUTCString() }); } // var weekNumber = "week + " " + year"; //"35 2020" const weekNumber = "53 2020"; const weekYearArr = weekNumber.split(" ").map(n => parseInt(n)) const weekOut = getISOWeek(...weekYearArr) console.log(weekOut);

输入：“35 2020”

输出：

[
  "Sun, 23 Aug 2020 22:00:00 GMT",
  "Mon, 24 Aug 2020 22:00:00 GMT",
  "Tue, 25 Aug 2020 22:00:00 GMT",
  "Wed, 26 Aug 2020 22:00:00 GMT",
  "Thu, 27 Aug 2020 22:00:00 GMT",
  "Fri, 28 Aug 2020 22:00:00 GMT",
  "Sat, 29 Aug 2020 22:00:00 GMT"
]

输入：“36 2020”

输出：

[
  "Sun, 30 Aug 2020 22:00:00 GMT",
  "Mon, 31 Aug 2020 22:00:00 GMT",
  "Tue, 01 Sep 2020 22:00:00 GMT",
  "Wed, 02 Sep 2020 22:00:00 GMT",
  "Thu, 03 Sep 2020 22:00:00 GMT",
  "Fri, 04 Sep 2020 22:00:00 GMT",
  "Sat, 05 Sep 2020 22:00:00 GMT"
]