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Laravel 合并数组内的数组

[英]Laravel merge arrays inside an array

我有这样的结果

array:2 [
  0 => array:5 [
    0 => 3
    1 => 7
    2 => 8
    3 => 9
    4 => 10
  ]
  1 => array:1 [
    0 => 216
  ]
]

我想要这样:

array:6 [
    0 => 3
    1 => 7
    2 => 8
    3 => 9
    4 => 10
    5 => 216
]

我应该如何更改我的代码?

$barcodes = [];
foreach($request->input('serials') as $serial)
{
    if(!empty($serial['barcode_id'])) {
        if($serial['amount'] > 1) {
            $barcodes[] = Barcode::where('sold', true)->take($serial['amount'])->pluck('id')->toArray(); // returned `0 => array:5 [`
        } else {
            $barcodes[] = Barcode::where('sold', true)->where('serial_number', $serial['barcode_id'])->orWhere('u_serial_number', $serial['barcode_id'])->pluck('id')->toArray(); // returned `1 => array:1 [`
        }
    }
}
dd($barcodes);

您可以直接在循环中执行此操作:

$barcodes = [];
foreach($request->input('serials') as $serial)
{
    if(!empty($serial['barcode_id'])) {
        if($serial['amount'] > 1) {
            $barcodes = array_merge($barcodes, Barcode::where('sold', true)->take($serial['amount'])->pluck('id')->toArray());
        } else {
            $barcodes = array_merge($barcodes, Barcode::where('sold', true)->where('serial_number', $serial['barcode_id'])->orWhere('u_serial_number', $serial['barcode_id'])->pluck('id')->toArray());
        }
    }
}

解决了

解决方案是使用...运算符合并我的内部数组

array_merge(...$barcodes)并完成了这项工作。

也许是一种更幼稚的方式;

//Bring in Arr facade
use Illuminate\Support\Arr;
//Then
Arr::flatten($barcodes);

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