Laravel 合並數組內的數組

Question

我有這樣的結果

array:2 [
  0 => array:5 [
    0 => 3
    1 => 7
    2 => 8
    3 => 9
    4 => 10
  ]
  1 => array:1 [
    0 => 216
  ]
]

我想要這樣：

array:6 [
    0 => 3
    1 => 7
    2 => 8
    3 => 9
    4 => 10
    5 => 216
]

我應該如何更改我的代碼？

$barcodes = [];
foreach($request->input('serials') as $serial)
{
    if(!empty($serial['barcode_id'])) {
        if($serial['amount'] > 1) {
            $barcodes[] = Barcode::where('sold', true)->take($serial['amount'])->pluck('id')->toArray(); // returned `0 => array:5 [`
        } else {
            $barcodes[] = Barcode::where('sold', true)->where('serial_number', $serial['barcode_id'])->orWhere('u_serial_number', $serial['barcode_id'])->pluck('id')->toArray(); // returned `1 => array:1 [`
        }
    }
}
dd($barcodes);

Answer 1

您可以直接在循環中執行此操作：

$barcodes = [];
foreach($request->input('serials') as $serial)
{
    if(!empty($serial['barcode_id'])) {
        if($serial['amount'] > 1) {
            $barcodes = array_merge($barcodes, Barcode::where('sold', true)->take($serial['amount'])->pluck('id')->toArray());
        } else {
            $barcodes = array_merge($barcodes, Barcode::where('sold', true)->where('serial_number', $serial['barcode_id'])->orWhere('u_serial_number', $serial['barcode_id'])->pluck('id')->toArray());
        }
    }
}

Answer 2

解決了

解決方案是使用...運算符合並我的內部數組

array_merge(...$barcodes)並完成了這項工作。

Answer 3

也許是一種更幼稚的方式；

//Bring in Arr facade
use Illuminate\Support\Arr;
//Then
Arr::flatten($barcodes);