如何在文本中查找特定单词并使用 python 计算它们？

Question

我想检查某些单词是否出现在输入文本中，如果出现，出现了多少次。

这些是我的投入：

• 单词列表： keywords = ["apple", "banana", "orange", "lemon"]
• 要扫描的text = "This apple is very tasty but the banana is not delicious at all." ： text = "This apple is very tasty but the banana is not delicious at all."

现在我想计算关键字列表中的单词出现在输入文本中的次数。

所以这个例子的输出应该是这样的：

`我找到了2个词。

这是我到目前为止所得到的，但在这种情况下它输出的是 0 而不是 2。

text = "This apple is very tasty but the banana is not delicious at all."

keywords = ["apple", "banana", "orange", "lemon"]

def dictionary_score(text):
    wordcount=0
    for line in text:
        line = line.strip()
        line = line.lower()
        words = line.split(" ")
        for word in words:
            if keywords in words:
                wordcount += 1
print(f"I found {wordcount} words") 

正确计数的问题在哪里？

Answer 1

问题在于if keywords in words: 。 它会检查整个keywords列表是否在您的words列表中。

您可能想检查每个word是否在keywords列表中：

if word in keywords:

Answer 2

1. text是一个字符串，并且for line in text迭代字符串的字符。 可以替换for line in text.splitlines():的for line in text.splitlines():

2. 应该是if word in keywords:而不是if word in keywords:的if keywords in words:

    text = "This apple is very tasty but the banana is not delicious at all." keywords = ["apple", "banana", "orange", "lemon"] def dictionary_score(text): wordcount=0 for line in text.splitlines(): print(line) line = line.strip() line = line.lower() words = line.split(" ") for word in words: if word in keywords: wordcount += 1 print(f"I found {wordcount} words") dictionary_score(text)```

输出： I found 2 words

Answer 3

您的代码有几个错误：

text = "This apple is very tasty but the banana is not delicious at all."
keywords = ["apple", "banana", "orange", "lemon"]

def dictionary_score(text):
    wordcount=0
    for line in text: #Iterate over each string character
        line = line.strip()
        line = line.lower()
        words = line.split(" ") #Here the list will be empty, because you are operating on a character.
        for word in words: #You are iterating over a empty list
            if keywords in words: #Checking if the list keywords is in words(that is empty)
                wordcount += 1
print(f"I found {wordcount} words") 

• for line in text:迭代字符串的每个字符，在获取字符串后，降低并拆分它。

• if keywords in words:这里您检查关键字列表是否在词列表中，因为前面的解释是空的。

这里是固定代码：

text = "This apple is very tasty but the banana is not delicious at all."
keywords = ["apple", "banana", "orange", "lemon"]

def dictionary_score(text):
    wordcount = 0
    words = text.strip().lower().split(" ") #split the string, after stripping and lowering it
    for word in words: # Iterate over the words
        if word in keywords: # If the word is in the keywords list increment the counter
            wordcount += 1
    print(f"I found {wordcount} words") 

dictionary_score(text)

输出： I found 2 words

Answer 4

在集合中使用计数器

from collections import Counter
text = "This apple is very tasty but the banana is not delicious at all."
dict_words = Counter(text.split(" "))
dict_word.get("apple", 0 ) #Get the word count for apple