Matplotlib 散点图，每个点都有不同的文本

Question

假设我有 3 个系列

>>> df[df['Type']=="Machine Learning"]['Cost']
0     2300.00
1     3200.00
4     1350.00
7     1352.00
8     4056.00
9       79.00
10    1595.00
Name: Cost, dtype: float64
>>>df[df['Type']=="Machine Learning"]['Rank']
0      1
1      1
4      1
7      2
8      2
9      2
10     2
Name: Rank, dtype: int64
>>>df[df['Type']=="Machine Learning"]['Univ/Org']
0     Massachusetts Institute of Technology 
1     Massachusetts Institute of Technology 
4                                    EDX/MIT
7                        Stanford University
8                        Stanford University
9               Coursera/Stanford University
10                       Stanford University
Name: Univ/Org, dtype: object

现在我想绘制一个散点图，y 轴为成本，X 轴为排名，每个数据点的大学/组织名称。

现在我在提到这个问题后还能做的是

plt.scatter(df[df['Type']=="Machine Learning"]['Rank'], df[df['Type']=="Machine Learning"]['Cost'],marker='2', edgecolors='black')
for i, txt in enumerate(df[df['Type']=="Machine Learning"]['Univ/Org']):
    plt.annotate(txt, (df[df['Type']=="Machine Learning"]['Rank'][i], df[df['Type']=="Machine Learning"]['Cost'][i]))

它正在命名 2 个数据点，然后给出错误。

情节是：

错误是：

---------------------------------------------------------------------------
KeyError                                  Traceback (most recent call last)
<ipython-input-111-0d31107a166a> in <module>
      1 plt.scatter(df[df['Type']=="Machine Learning"]['Rank'], df[df['Type']=="Machine Learning"]['Cost'],marker='2', edgecolors='black')
      2 for i, txt in enumerate(df[df['Type']=="Machine Learning"]['Univ/Org']):
----> 3     plt.annotate(txt, (df[df['Type']=="Machine Learning"]['Rank'][i], df[df['Type']=="Machine Learning"]['Cost'][i]))

~/anaconda3/lib/python3.8/site-packages/pandas/core/series.py in __getitem__(self, key)
    869         key = com.apply_if_callable(key, self)
    870         try:
--> 871             result = self.index.get_value(self, key)
    872 
    873             if not is_scalar(result):

~/anaconda3/lib/python3.8/site-packages/pandas/core/indexes/base.py in get_value(self, series, key)
   4403         k = self._convert_scalar_indexer(k, kind="getitem")
   4404         try:
-> 4405             return self._engine.get_value(s, k, tz=getattr(series.dtype, "tz", None))
   4406         except KeyError as e1:
   4407             if len(self) > 0 and (self.holds_integer() or self.is_boolean()):

pandas/_libs/index.pyx in pandas._libs.index.IndexEngine.get_value()

pandas/_libs/index.pyx in pandas._libs.index.IndexEngine.get_value()

pandas/_libs/index.pyx in pandas._libs.index.IndexEngine.get_loc()

pandas/_libs/hashtable_class_helper.pxi in pandas._libs.hashtable.Int64HashTable.get_item()

pandas/_libs/hashtable_class_helper.pxi in pandas._libs.hashtable.Int64HashTable.get_item()

KeyError: 2

Answer 1

几件事。

首先，我建议您将 ML 数据选择到一个新的数据框中。 您还应该使用.loc和.at访问器来更精确一些。 所以像这样：

mldf = df.loc[df['Type'] == "Machine Learning", :]

fig, ax = plt.sunplots()
ax.scatter('Rank', 'Cost', data=mldf, marker='2', edgecolors='black')
for i in mldf.index:
    ax.annotate(mldf.at[i, 'Univ/Org'], (mldf.at[i, 'Rank'], mldf.at[i, 'Cost'])