[英]How to return string from “for loop”? Objective-C iOS
我是 Objective-C 语言编程的新手。
我需要从函数中的for loop
返回这个“tabName”。 如何比较app_additional_tab_name_
是否等于 tabName? 因为现在仍然返回任何app_additional_tab_name_
。
+ (NSString *)additionalTabName {
for (int i = 0; i <= 16; i++) {
tabNameConcatString = [NSMutableString stringWithFormat:@"app_additional_tab_name_%d", i];
tabName = [LocalizedStringsUserDefaults valueForKey:tabNameConcatString];
if ([LocalizedStringsUserDefaults existsObjectForKey:tabNameConcatString]) {
tabName = [LocalizedStringsUserDefaults valueForKey:tabNameConcatString];
NSLog(@"This tabName is: @% @% @% @%", tabName, @" and will append to: ", tabNameConcatString);
}
}
return tabName;
}
祝一切顺利。
在匹配条件内移动 return
+ (NSString *)additionalTabName {
for (int i = 0; i <= 16; i++) {
tabNameConcatString = [NSMutableString stringWithFormat:@"app_additional_tab_name_%d", i];
tabName = [LocalizedStringsUserDefaults valueForKey:tabNameConcatString];
if ([LocalizedStringsUserDefaults existsObjectForKey:tabNameConcatString]) {
tabName = [LocalizedStringsUserDefaults valueForKey:tabNameConcatString];
NSLog(@"This tabName is: @% @% @% @%", tabName, @" and will append to: ", tabNameConcatString);
return tabName;
}
}
return nil;
}
如果没有找到匹配项,您可以返回 nil 或返回空字符串。
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.