![](/img/trans.png)
[英]How to get the latest records of the multiple values of same column in PostgreSQL?
[英]How to fetch the latest records in PostgreSQL?
实际上我正在尝试通过r_id
和最新的start_date
获取这些数据的最新记录
我的样本数据:
**r_id** **s_id ** **start_date**
"149165" "28317" "2020-09-07 08:12:46.108"
"149165" "28324" "2020-09-07 08:18:15.934"
"149161" "28313" "2020-09-07 08:11:33.923"
"149161" "28316" "2020-09-07 08:12:19.887"
"149161" "28312" "2020-09-07 08:11:04.448"
"149161" "28305" "2020-09-07 08:09:17.211"
预期成绩 :
**r_id** **s_id ** **start_date**
"149165" "28324" "2020-09-07 08:18:15.934"
"149161" "28316" "2020-09-07 08:12:19.887"
任何人请。
您可以使用distinct on
:
select distinct on (r_id) t.*
from mytable t
order by r_id, start_date desc
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.