Python：在熊猫系列中连接以逗号分隔的字符串

Question

使用 TextBlob 拼写校正器后，每行中的句子用逗号分隔。

from textblob import TextBlob
list = df['sentence'].tolist()

def TBSpellCorrector(sentence):
    b = TextBlob(sentence)
    return b.correct()

df['corrected_sentence']=df['sentence'].apply(TBSpellCorrector)

结果：

    sentence         corrected_sentence
132 on fre     (o, n,, f, i, r, e)             
35  beautful    (b, e, a, u, t, i, f, u, l)    

我需要连接以逗号分隔的句子。

Expected Output
    sentence         corrected_sentence        corrected_sentence2
132 on fre           (o, n,, f, i, r, e)             on fire
35  beautful    (b, e, a, u, t, i, f, u, l)         beautiful

Answer 1

如果correct_sentence为以列表的形式，你可以加入他们join

>>> sent = ['o','n',' ','f','i','r','e']
>>> ''.join(sent)
'on fire'

Answer 2

.correct()方法返回一个textblob.blob.TextBlob对象。 你只需要将它转换为一个字符串，或者访问它的.string属性：

from textblob import TextBlob
import pandas as pd

def TBSpellCorrector(sentence):
    return TextBlob(sentence).correct().string # <<< See here

df = pd.DataFrame({'sentence':['on fre','beautful']})
df['sentence'].apply(TBSpellCorrector)
# 0       on are
# 1    beautiful
# Name: sentence, dtype: object