[英]Selenium find_elements By.XPATH trying to extract href urls error
使用 Firefox webdriver,我想从包含单词a href
中提取所有 URL。 我正在使用最新的硒二进制文件。 试过这个:
driver = webdriver.Firefox()
driver.get(url)
nodes = driver.find_elements(By.XPATH, "//a[contains(@href,'products')]/@href")
print("nodes: ", nodes)
links = []
for elem in nodes:
links.append(elem)
但得到一个类型错误:
selenium.common.exceptions.WebDriverException: Message: TypeError: Expected an element or WindowProxy, got: [object Attr href="https://www.example.com/catalogue/products/a.html"]
还尝试了driver.find_elements(By.XPATH, "//a[contains(@href,'products')]")
然后对每个使用getAttribute("href")
,但也不能。
不明白错误在哪里以及如何解决这个问题。
html的摘录:
<html>
<body>
<ul class="level2-megamenu">
<li>
<div class="level1-title">
<a href="https://www.example.com/catalogue/products/a.html">
<strong style="color:#828282;font-size:>Text</strong>
</a>
</div>
</li>
</ul>
</body>
</html>
要使用Selenium和python提取href
属性,您必须为visibility_of_all_elements_located()
引入WebDriverWait ,您可以使用以下任一定位器策略:
使用CSS_SELECTOR
:
print([my_elem.get_attribute("href") for my_elem in WebDriverWait(driver, 20).until(EC.visibility_of_all_elements_located((By.CSS_SELECTOR, "a[href*='products']")))])
使用XPATH
:
print([my_elem.get_attribute("href") for my_elem in WebDriverWait(driver, 20).until(EC.visibility_of_all_elements_located((By.XPATH, "//a[contains(@href,'products')]")))])
注意:您必须添加以下导入:
from selenium.webdriver.support.ui import WebDriverWait from selenium.webdriver.common.by import By from selenium.webdriver.support import expected_conditions as EC
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