[英]cannot find symbol in android studio while connecting to firebase
当我尝试将我的应用程序连接到数据库时,它显示了找不到符号的错误。
error: cannot find symbol
String ownerName = ownerName.getEditText().getText().toString();
^
symbol: method getEditText()
location: variable ownerName of type String
下面是我的代码
public class merchantRegistrationForm extends AppCompatActivity implements View.OnClickListener {
EditText ownerName, phoneNumber, emailId, password, cnfPassword;
DatabaseReference databaseReference;
FirebaseAuth firebaseAuth;
FirebaseDatabase rootNode;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_merchant_registration_form);
ownerName = findViewById(R.id.ownerName);
phoneNumber = findViewById(R.id.ownerPhoneNumber);
emailId = findViewById(R.id.ownerEmailId);
password =findViewById(R.id.password);
cnfPassword =findViewById(R.id.confirmPassword);
Button goNext;
goNext = findViewById(R.id.nextToBusinessSelector);
goNext.setOnClickListener(this);
databaseReference = FirebaseDatabase.getInstance().getReference("merchant Signup");
goNext.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
rootNode = FirebaseDatabase.getInstance();
databaseReference = rootNode.getReference();
String ownerName = ownerName.getEditText().getText().toString();
String phoneNumber = phoneNumber.getEditText().getText().toString();
String emailId = emailId.getEditText().getText().toString();
String password = password.getEditText().getText().toString();
String cnfPassword = cnfPassword.getEditText().getText().toString();
merchantsignup helperclass = new merchantsignup(ownerName, phoneNumber,emailId, password, cnfPassword);
databaseReference.setValue("hello");
}
});
Intent intent = new Intent(merchantRegistrationForm.this, salonDetails.class);
startActivity(intent);
Toast.makeText(this, "Few Steps more", Toast.LENGTH_LONG).show();
}
@Override
public void onClick(View view) {
}
}
您的代码令人困惑,因为您最初将ownerName
声明为 EditText:
EditText ownerName;
但随后将其重新定义为字符串:
String ownerName = ownerName.getEditText().getText().toString();
错误消息告诉您 String 对象上没有getEditText()
方法。 也许您想为字符串变量使用不同的名称。
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